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Question 10
Table 4 shows some electrode half-equations and their standard electrode potentials. Electrode half-equation E° / V Cl2(g) + 2e⁻ → 2Cl⁻(aq) ... show full transcript
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Answer
An acid that will oxidise copper is nitric acid (HNO3).
Explanation: Nitric acid is a stronger oxidizing agent as it contains NO3⁻ which can readily react with copper.
Balanced Equation: 3Cu + 8H⁺ + 2NO3⁻ → 3Cu²⁺ + 2NO + 4H2O
EMF Calculation: The overall EMF for the reaction is calculated as follows:
For the half-reactions:
Combining these, we get:
EMF = (E° for reduction) - (E° for oxidation) = 0.96 V - 0.34 V = 0.62 V.
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