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What is the minimum volume, in cm³, of 0.02 mol dm⁻³ KMnO₄ solution needed to oxidise 0.01 mol of VO²⁺? 5 VO²⁺ + MnO₄⁻ + H₂O → 5 VO₃ + Mn²⁺ + 2 H⁺ - AQA - A-Level Chemistry - Question 31 - 2020 - Paper 3
Question 31
What is the minimum volume, in cm³, of 0.02 mol dm⁻³ KMnO₄ solution needed to oxidise 0.01 mol of VO²⁺? 5 VO²⁺ + MnO₄⁻ + H₂O → 5 VO₃ + Mn²⁺ + 2 H⁺
Worked Solution & Example Answer:What is the minimum volume, in cm³, of 0.02 mol dm⁻³ KMnO₄ solution needed to oxidise 0.01 mol of VO²⁺? 5 VO²⁺ + MnO₄⁻ + H₂O → 5 VO₃ + Mn²⁺ + 2 H⁺ - AQA - A-Level Chemistry - Question 31 - 2020 - Paper 3
Step 1
Step 2
Use Concentration to Find Volume
Answer
We use the equation ( C = \frac{n}{V} ) to find the volume needed:
[ V = \frac{n}{C} ]
Substituting the values:
[ V = \frac{0.002, \text{mol}}{0.02, \text{mol dm}^{-3}} = 0.1, ext{dm}^3 ]
Since we need the volume in cm³:
[ V = 0.1, ext{dm}^3 \times 1000 = 100, ext{cm}^3 ]