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The equation for the reaction between zinc and hydrochloric acid is Zn + 2HCl → ZnCl₂ + H₂ What is the minimum mass, in mg, of zinc (Ar = 85.4) needed to react with 50.0 cm³ of 1.68 mol dm⁻³ hydrochloric acid? - AQA - A-Level Chemistry - Question 19 - 2017 - Paper 3

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The-equation-for-the-reaction-between-zinc-and-hydrochloric-acid-is--Zn-+-2HCl-→-ZnCl₂-+-H₂--What-is-the-minimum-mass,-in-mg,-of-zinc-(Ar-=-85.4)-needed-to-react-with-50.0-cm³-of-1.68-mol-dm⁻³-hydrochloric-acid?-AQA-A-Level Chemistry-Question 19-2017-Paper 3.png

The equation for the reaction between zinc and hydrochloric acid is Zn + 2HCl → ZnCl₂ + H₂ What is the minimum mass, in mg, of zinc (Ar = 85.4) needed to react wit... show full transcript

Worked Solution & Example Answer:The equation for the reaction between zinc and hydrochloric acid is Zn + 2HCl → ZnCl₂ + H₂ What is the minimum mass, in mg, of zinc (Ar = 85.4) needed to react with 50.0 cm³ of 1.68 mol dm⁻³ hydrochloric acid? - AQA - A-Level Chemistry - Question 19 - 2017 - Paper 3

Step 1

Calculate the moles of hydrochloric acid

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Answer

To determine the moles of hydrochloric acid (HCl), we use the formula:

extMoles=extConcentrationimesextVolume ext{Moles} = ext{Concentration} imes ext{Volume}

Given:

  • Concentration = 1.68 mol dm⁻³
  • Volume = 50.0 cm³ = 0.0500 dm³ (since 1000 cm³ = 1 dm³)

Now substituting the values:

extMolesHCl=1.68imes0.0500=0.084extmol ext{Moles HCl} = 1.68 imes 0.0500 = 0.084 ext{ mol}

Step 2

Determine the moles of zinc needed

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Answer

From the balanced equation:

extZn+2extHClightarrowextZnCl2+extH2 ext{Zn} + 2 ext{HCl} ightarrow ext{ZnCl}_2 + ext{H}_2

This shows that 1 mole of zinc reacts with 2 moles of hydrochloric acid. Thus, the moles of zinc required can be calculated as:

ext{Moles Zn} = rac{0.084 ext{ mol HCl}}{2} = 0.042 ext{ mol Zn}

Step 3

Calculate the mass of zinc needed

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Answer

Using the atomic mass of zinc (Ar = 65.4 g/mol), the mass of zinc can be calculated using:

extMass=extMolesimesextMolarMass ext{Mass} = ext{Moles} imes ext{Molar Mass}

Substituting the values:

extMassZn=0.042extmolimes65.4extg/mol=2.748extg ext{Mass Zn} = 0.042 ext{ mol} imes 65.4 ext{ g/mol} = 2.748 ext{ g}

Since the answer is required in mg:

extMassinmg=2.748extgimes1000=2748extmg ext{Mass in mg} = 2.748 ext{ g} imes 1000 = 2748 ext{ mg}

Step 4

Final Answer

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Answer

The minimum mass of zinc needed is approximately 2.75 mg.

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