Photo AI

Give an equation for the reaction of solid sodium bromide with concentrated sulfuric acid to form bromine - AQA - A-Level Chemistry - Question 4 - 2021 - Paper 3

Question icon

Question 4

Give-an-equation-for-the-reaction-of-solid-sodium-bromide-with-concentrated-sulfuric-acid-to-form-bromine-AQA-A-Level Chemistry-Question 4-2021-Paper 3.png

Give an equation for the reaction of solid sodium bromide with concentrated sulfuric acid to form bromine. Equation Observation A solution that is thought to cont... show full transcript

Worked Solution & Example Answer:Give an equation for the reaction of solid sodium bromide with concentrated sulfuric acid to form bromine - AQA - A-Level Chemistry - Question 4 - 2021 - Paper 3

Step 1

Give an equation for the reaction of solid sodium bromide with concentrated sulfuric acid to form bromine.

96%

114 rated

Answer

The equation for the reaction is:

2NaBr+H2SO4Na2SO4+2HBr+Br22NaBr + H_2SO_4 \rightarrow Na_2SO_4 + 2HBr + Br_2

Here, sodium bromide reacts with concentrated sulfuric acid to produce sodium sulfate, hydrogen bromide, and bromine gas.

Step 2

State one observation made during this reaction.

99%

104 rated

Answer

During the reaction, orange/brown fumes of bromine are observed, indicating the formation of bromine gas.

Step 3

Give a reason for the use of each reagent.

96%

101 rated

Answer

  1. Dilute nitric acid is used to remove any unwanted ions that may interfere with the subsequent tests for halides.
  2. Aqueous silver nitrate is added to precipitate chloride and iodide ions as silver chloride and silver iodide, respectively. This is crucial for identifying halides in the solution.
  3. A dilute solution of ammonia is added to distinguish between silver chloride and silver iodide; silver chloride dissolves in ammonia, while silver iodide does not.

Step 4

Explain the observations.

98%

120 rated

Answer

The formation of a pale yellow precipitate indicates the presence of silver iodide, which is less soluble and precipitates in the presence of iodide ions. The excess ammonia dissolves the silver chloride precipitate, confirming its identity as it reacts to form a soluble silver ammine complex while leaving the silver iodide intact.

Step 5

Give ionic equations for any reactions.

97%

117 rated

Answer

  1. The reaction of chloride ions with silver nitrate can be represented as:

Ag+(aq)+Cl(aq)AgCl(s)Ag^+ (aq) + Cl^- (aq) \rightarrow AgCl (s)

  1. In the presence of ammonia, the dissolution of silver chloride can be expressed as:

AgCl(s)+2NH3(aq)[Ag(NH3)2]+(aq)+Cl(aq)AgCl (s) + 2NH_3 (aq) \rightarrow [Ag(NH_3)_2]^+ (aq) + Cl^- (aq)

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;