Concentrated sulfuric acid reacts with alkenes, alcohols and sodium halides - AQA - A-Level Chemistry - Question 2 - 2017 - Paper 3
Question 2
Concentrated sulfuric acid reacts with alkenes, alcohols and sodium halides.
2.1 Name the mechanism for the reaction of concentrated sulfuric acid with an alkene.
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Worked Solution & Example Answer:Concentrated sulfuric acid reacts with alkenes, alcohols and sodium halides - AQA - A-Level Chemistry - Question 2 - 2017 - Paper 3
Step 1
Name the mechanism for the reaction of concentrated sulfuric acid with an alkene.
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Answer
The mechanism for the reaction of concentrated sulfuric acid with an alkene is known as electrophilic addition.
Step 2
Outline the mechanism for the reaction of concentrated sulfuric acid with propene to show the formation of the major product.
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Answer
Protonation of Propene: The pi bond of propene attacks a hydrogen ion (H+) from sulfuric acid, forming a carbocation.
Carbocation Formation: The more stable secondary carbocation is formed when the H+ attaches to the terminal carbon, leading to either a primary or a secondary carbocation in branching scenarios.
Nucleophilic Attack: The bisulfate ion (HSO4-) then attacks the carbocation, leading to the formation of the major product—alkyl hydrogen sulfate.
Product Formation: The alkyl hydrogen sulfate can further undergo hydrolysis to give the corresponding alcohol.
Step 3
Draw the structure of the minor product of the reaction between concentrated sulfuric acid and propene.
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Answer
The minor product can be represented as follows:
H O
\ |
C--C
/
H
This product arises from the formation of a different carbocation due to the protonation site.
Step 4
Explain why the product shown in your answer to Question 2.2 is the major product.
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The product shown is the major product due to the greater stability of the secondary carbocation formed during the reaction process. Secondary carbocations are more stable than primary ones due to hyperconjugation and inductive effects from adjacent carbon groups.
Step 5
Draw the skeletal formula of each of the three isomeric alkenes formed by the reaction of butan-2-ol with concentrated sulfuric acid. Give the full IUPAC name of each isomer.
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Isomer 1:
H H
\ |
C=C
/
H C
|
H
Name: 2-butene
Isomer 2:
H H
\|
C=C
/
H C
|
H
Name: E-but-2-ene (trans)
Isomer 3:
H H
\ |
C=C
/
H H
Name: Z-but-2-ene (cis)
Step 6
Name this by-product, identify the role of the sulfuric acid in its formation and suggest the name of a method that could be used to separate the products of this reaction.
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Answer
By-product: The by-product is butanol (C4H10O).
Role of sulfuric acid: The sulfuric acid acts as a dehydrating agent, facilitating the conversion of alcohol to alkene and producing water as a by-product.
Name of separation method:Distillation could be used to separate the products of this reaction.
Step 7
Give the observation you would make in this reaction. State the role of the sulfuric acid.
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Observation with sodium chloride: The reaction produces white fumes of hydrogen chloride gas and may form a solid residue.
Role of sulfuric acid: It acts as a catalyst and proton donor, enabling the reaction of sodium chloride to produce HCl.
Step 8
Observations made during this reaction include the formation of a black solid, a yellow solid and a gas with the smell of bad eggs.
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Black solid: This is typically elemental iodine.
Yellow solid: This refers to sulfur.
Gas: The gas observed is hydrogen sulfide (H2S), which is known for its characteristic smell of rotten eggs.