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Paracetamol is a medicine commonly used to relieve mild pain - AQA - A-Level Chemistry - Question 8 - 2019 - Paper 2

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Paracetamol is a medicine commonly used to relieve mild pain. Traditionally, paracetamol has been made industrially in a three-step synthesis from phenol. Step 1 S... show full transcript

Worked Solution & Example Answer:Paracetamol is a medicine commonly used to relieve mild pain - AQA - A-Level Chemistry - Question 8 - 2019 - Paper 2

Step 1

Name the mechanism of the reaction in Step 1.

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Answer

The mechanism of the reaction in Step 1 is electrophilic substitution.

Step 2

Complete the equation for the reaction in Step 2.

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Answer

The complete equation for the reaction in Step 2 can be represented as:

4-aminophenol+NO2(conc.)→4-nitrophenol+H2O\text{4-aminophenol} + \text{NO}_2\text{(conc.)} \rightarrow \text{4-nitrophenol} + \text{H}_2\text{O}

Step 3

Complete the mechanism for the reaction of 4-aminophenol with ethanoyl chloride.

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Answer

The mechanism involves the nucleophilic attack of the ammonium component of 4-aminophenol on the carbon atom of the carbonyl group in ethanoyl chloride, leading to the formation of paracetamol.

Step 4

Give one reason why ethanoyl chloride is not used in the industrial synthesis.

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Answer

One reason why ethanoyl chloride is not used in the industrial synthesis is because it is corrosive and poses a risk to health and safety during its handling.

Step 5

Draw the structure of one of these other aromatic products.

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Answer

One possible structure of an aromatic product is 4-nitrochlorobenzene:

    Cl
     | 
   C6H4
     | 
    NO2

Alternatively, another product might be 2-nitrophenol.

Step 6

Complete the equation for this second step.

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Answer

The complete equation for the second step is:

hydroquinone+NH4OEt→paracetamol+H2O\text{hydroquinone} + \text{NH}_4\text{OEt} \rightarrow \text{paracetamol} + \text{H}_2\text{O}

Step 7

Calculate the mass, in kg, of hydroquinone needed to produce 250 kg of paracetamol.

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Answer

To find the mass of hydroquinone needed:

  1. Calculate moles of paracetamol: Moles of paracetamol=250000g151.0g/mol=1655.6 mol\text{Moles of paracetamol} = \frac{250000 \text{g}}{151.0 \text{g/mol}} = 1655.6 \text{ mol}

  2. Use stoichiometry to find moles of hydroquinone, which is equal to moles of paracetamol: Moles of hydroquinone=1655.6 mol\text{Moles of hydroquinone} = 1655.6 \text{ mol}

  3. Calculate mass of hydroquinone: Mass of hydroquinone=1655.6 mol×110.0 g/mol=18211.9 g=18.2 kg\text{Mass of hydroquinone} = 1655.6 \text{ mol} \times 110.0 \text{ g/mol} = 18211.9 \text{ g} = 18.2 \text{ kg}

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