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Figure 1 represents the cell used to measure the standard electrode potential for the Fe²⁺/Fe electrode - AQA - A-Level Chemistry - Question 3 - 2019 - Paper 3

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Figure 1 represents the cell used to measure the standard electrode potential for the Fe²⁺/Fe electrode. 0 3.1 Name the piece of apparatus labelled A. 0 3.2 State ... show full transcript

Worked Solution & Example Answer:Figure 1 represents the cell used to measure the standard electrode potential for the Fe²⁺/Fe electrode - AQA - A-Level Chemistry - Question 3 - 2019 - Paper 3

Step 1

Name the piece of apparatus labelled A.

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Answer

The piece of apparatus labelled A is a salt bridge.

Step 2

State the purpose of A.

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Answer

The purpose of A (the salt bridge) is to complete the circuit by allowing the flow of ions, which maintains electrical neutrality in the cell.

Step 3

Name the substance used as electrode B in Figure 1.

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Answer

Electrode B is made of platinum.

Step 4

Complete Table 1 to identify C, D and E from Figure 1. Include the essential conditions for each.

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Answer

IdentityConditions
C1 mol dm⁻³
D100 kPa
E1 mol dm⁻³

Step 5

Give the ionic equation for the overall reaction in Figure 1.

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Answer

The ionic equation for the overall reaction in Figure 1 is:

ightleftharpoons ext{Fe}$$

Step 6

State the change that needs to be made to the apparatus in Figure 1 to allow the cell reaction to go to completion.

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Answer

To allow the cell reaction to go to completion, the solution in the cell must be changed to maintain the concentration of reactants or remove products.

Step 7

Complete Table 2 to show the value missing from experiment 4.

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Answer

Experiment[Zn²⁺] mol dm⁻³[Cu²⁺] mol dm⁻³Ecell / V
41.000.001.04

Step 8

Calculate the gradient of your plotted line on the graph in question 0 3.6.

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The gradient of the plotted line should be calculated based on the derived points from the graph, which will yield a value of approximately -0.013 V.

Step 9

Use your gradient to calculate the temperature, T, at which the measurements of Ecell were taken.

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Answer

Using the gradient value in the equation: Ecell=(4.3imes105imesT)+E°cellE_{cell} = (-4.3 imes 10^{-5} imes T) + E°_{cell} we can rearrange to find T. Given the gradient is -0.013 V, we set the equation to find T: T = rac{E° - E_{cell}}{-4.3 imes 10^{-5}} Using the value -0.013, we would find T to be approximately 302.0 K.

Step 10

Calculate the electrode potential for the Zn²⁺/Zn electrode in experiment 2.

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For experiment 2: EZn2+/Zn=EcellECu2+/CuE_{Zn^{2+}/Zn} = E_{cell} - E_{Cu^{2+}/Cu} Substituting the values gives: EZn2+/Zn=1.04V0.33V=0.71VE_{Zn^{2+}/Zn} = 1.04 V - 0.33 V = 0.71 V

Step 11

Give one reason why your calculated value is different from the standard electrode potential for Zn²⁺/Zn electrode.

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Answer

The calculated value may differ from the standard electrode potential due to varying concentration conditions in the experiment compared to standard conditions.

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