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Question 23
Which compound has E-Z isomers? A CH two =CHBr B CH two =CBR two C CHBr=CHBr D CBr two=CHBr [1 mark]
Step 1
Answer
To determine which compound has E-Z isomers, we need to analyze each option to see if it has a double bond with substituents that qualify for E-Z configuration.
Option A (CH(_2)=CHBr): This compound has a double bond and two different substituents: Br and H on one carbon, and two H atoms on the other. Therefore, it cannot have E-Z isomers as one side does not have distinct substituents.
Option B (CH(_2)=CBR(_2)): Similar to option A, this has a double bond, but half the groups on one side are hydrogen atoms, making it incapable of E-Z isomerism.
Option C (CHBr=CHBr): This compound only has Br substituents, resulting in no distinction and preventing E-Z isomers.
Option D (CBr(_2)=CHBr): This compound has different substituents on the double bond (CBr(_2) and CHBr), clearly allowing for E-Z isomerism.
Thus, the correct answer is C CHBr=CHBr.
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