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Question 6
This question is about isomers with the molecular formula C\_5H\_10O. 6.1 Draw the skeletal formula of a branched chain aldehyde with molecular formula C\_5H\_10O t... show full transcript
Step 1
Answer
The skeletal formula for an optically active branched chain aldehyde C_5H_10O is:
CHO
|
CH3-CH-CH2-CH3
|
CH3
This structure has a chiral carbon atom that allows for optical activity.
Step 2
Answer
To distinguish between the two enantiomers of the branched chain aldehyde, you can use plane polarized light:
Step 3
Answer
The E and Z forms of the structural isomer can be represented as follows:
E isomer:
CH3 CHO
| |
CH3-C=C-CH2-CH3
| |
OH CH3
Z isomer:
CH3 CHO
| |
CH3-C=C-CH2-CH3
| |
OH CH3
In these structures, you can see the spatial arrangements of the substituents around the double bond, which determines whether it is the E or Z isomer.
Step 4
Answer
Two cyclic isomers of C_5H_10O with an ether functional group are:
Isomer 1:
C1 O
|
C2-C3
|
C4
Isomer 2:
C1 O
|
C2-C3-C4
|
C5
These cyclic structures will exhibit only three peaks in their 13C NMR spectra due to their symmetric nature.
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