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This question is about isomers with the molecular formula C\_5H\_10O - AQA - A-Level Chemistry - Question 6 - 2021 - Paper 2

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This question is about isomers with the molecular formula C\_5H\_10O. 6.1 Draw the skeletal formula of a branched chain aldehyde with molecular formula C\_5H\_10O t... show full transcript

Worked Solution & Example Answer:This question is about isomers with the molecular formula C\_5H\_10O - AQA - A-Level Chemistry - Question 6 - 2021 - Paper 2

Step 1

6.1 Draw the skeletal formula of a branched chain aldehyde with molecular formula C\_5H\_10O that is optically active.

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Answer

The skeletal formula for an optically active branched chain aldehyde C_5H_10O is:

      CHO
       |
   CH3-CH-CH2-CH3
       |
       CH3

This structure has a chiral carbon atom that allows for optical activity.

Step 2

6.2 Describe how you distinguish between separate samples of the two enantiomers of the branched chain aldehyde C\_5H\_10O.

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Answer

To distinguish between the two enantiomers of the branched chain aldehyde, you can use plane polarized light:

  1. Pass plane polarized light through a sample of one enantiomer.
  2. Measure the angle of rotation.
  3. Repeat the process with the second enantiomer.
  4. The two samples will rotate the plane of polarized light in opposite directions (one clockwise and the other counterclockwise).

Step 3

6.3 Draw the E and Z forms of a structural isomer of C\_5H\_10O that shows both optical and geometric isomerism.

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Answer

The E and Z forms of the structural isomer can be represented as follows:

E isomer:
    CH3          CHO
     |            |
  CH3-C=C-CH2-CH3
     |            |
    OH          CH3

Z isomer:
    CH3          CHO
     |            |
  CH3-C=C-CH2-CH3
     |            |
    OH          CH3

In these structures, you can see the spatial arrangements of the substituents around the double bond, which determines whether it is the E or Z isomer.

Step 4

6.4 Draw two other cyclic isomers of C\_5H\_10O that have an ether functional group and only three peaks in their 13C NMR spectra.

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Answer

Two cyclic isomers of C_5H_10O with an ether functional group are:

Isomer 1:
    C1   O
     |
   C2-C3
     |   
   C4   

Isomer 2:
    C1   O
     |
   C2-C3-C4
     |       
      C5    

These cyclic structures will exhibit only three peaks in their 13C NMR spectra due to their symmetric nature.

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