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Coconut oil contains a triester with three identical R groups - AQA - A-Level Chemistry - Question 1 - 2021 - Paper 2

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Coconut oil contains a triester with three identical R groups. This triester reacts with potassium hydroxide. RCOO–CH₂ + 3KOH → 3RCOOK + RCOO–CH + RCOO–CH₂ 1. Co... show full transcript

Worked Solution & Example Answer:Coconut oil contains a triester with three identical R groups - AQA - A-Level Chemistry - Question 1 - 2021 - Paper 2

Step 1

Complete the equation by drawing the structure of the other product of this reaction in the box.

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Answer

The other product of this reaction is the potassium salt of the fatty acid, which can be represented as:

K+RCOO\text{K}^+\text{RCOO}^-

This compound is a potassium carboxylate salt.

Step 2

Name the type of compound shown by the formula RCOOK

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Answer

The compound RCOOK is a potassium carboxylate salt.

Step 3

Give one use for this type of compound.

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Answer

One use for potassium carboxylate salts is in the production of soap, where they act as surfactants.

Step 4

Deduce the value of n in CH₃(CH₂)n.

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Answer

To determine the value of n:

  1. The molar mass of R, from the triester, can be calculated as follows:
    • M = 638 g/mol
    • R has a structure of CH₃(CH₂)n, where the mass contribution is: extC=12extg/mol,H=1extg/mol ext{C} = 12 ext{ g/mol, H} = 1 ext{ g/mol}
    • The approximate mass of the alkyl group R: 12+2n+1=12+2n+112 + 2n + 1 = 12 + 2n + 1
    • Therefore, we get: 638=3(12+2n+1)+58ext(weightofKandOatoms)638 = 3(12 + 2n + 1) + 58 ext{ (weight of K and O atoms)}
    • Solving gives n = 14.

Step 5

Calculate the percentage by mass of the triester (M=638.0) in the coconut oil.

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Answer

To find the percentage by mass:

  1. Calculate the amount of KOH reacted:
    • Moles of KOH = mass / molar mass = 0.421 g / 56.1 g/mol = 0.00749 mol
  2. Calculate the moles of HCl:
    • Moles of HCl = 15.65 cm³ × 0.100 mol/dm³ = 0.001565 mol
  3. Therefore, moles of KOH reacted is:
    • 0.00749 - 0.001565 = 0.005925 mol
  4. Molar mass of the triester = 638 g/mol
  5. Mass of triester in sample:
    • Mass = moles × molar mass = 0.005925 mol × 638 g/mol = 3.78 g
  6. Percentage by mass:
    • Percentage = (mass of triester / mass of coconut oil) × 100
    • Percentage = (3.78 g / 1.450 g) × 100 = 261.38%, which indicates the presence of more than one triester in the sample.

Step 6

Suggest why aqueous ethanol is a suitable solvent when heating the coconut oil with KOH.

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Answer

Aqueous ethanol is suitable because it allows the KOH to dissolve effectively and facilitates the hydrolysis of the triester.

Step 7

Give a safety precaution used when heating the mixture.

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Answer

One safety precaution when heating the mixture is to use a fume hood or ventilation to avoid inhalation of vapors.

Step 8

Justify your choice.

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Answer

Using a fume hood prevents the inhalation of harmful fumes or vapors produced during the heating process, thereby ensuring the safety of the experimenter.

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