Concentrated sulfuric acid reacts with alkenes, alcohols and sodium halides - AQA - A-Level Chemistry - Question 2 - 2017 - Paper 3
Question 2
Concentrated sulfuric acid reacts with alkenes, alcohols and sodium halides.
1. Name the mechanism for the reaction of concentrated sulfuric acid with an alkene.
2... show full transcript
Worked Solution & Example Answer:Concentrated sulfuric acid reacts with alkenes, alcohols and sodium halides - AQA - A-Level Chemistry - Question 2 - 2017 - Paper 3
Step 1
Name the mechanism for the reaction of concentrated sulfuric acid with an alkene.
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Answer
The mechanism for this reaction is known as electrophilic addition.
Step 2
Outline the mechanism for the reaction of concentrated sulfuric acid with propene to show the formation of the major product.
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Answer
Protonation: The concentrated sulfuric acid donates a proton (H⁺) to the double bond of propene, forming a carbocation.
Formation of Carbocation: The positive charge stabilizes the more substituted carbocation (secondary), leading to more stable product formation.
Nucleophilic Attack: The bisulfate ion (HSO₄⁻) then attacks the carbocation, leading to the formation of the major product—alkyl hydrogen sulfate.
Deprotonation: Finally, deprotonation takes place to yield the corresponding alkene.
Step 3
Draw the structure of the minor product of the reaction between concentrated sulfuric acid and propene.
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Answer
The minor product can be represented by the following structure, which results from the hydrogen adding to the less substituted carbon:
H H
| |
CH3-C=C-OSO3H
| |
H H
This corresponds to an alkyl hydrogen sulfate formed with substitution occurring at the less stable site.
Step 4
Explain why the product shown in your answer to Question 2.2 is the major product.
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The major product is favored due to the stability of the carbocation intermediate formed during the reaction. The more substituted carbocation is more stable because it is stabilized by hyperconjugation and inductive effects from adjacent alkyl groups. This leads to a greater rate of formation of the major product compared to the minor product.
Step 5
Draw the skeletal formula of each of the three isomeric alkenes formed by the reaction of butan-2-ol with concentrated sulfuric acid.
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H H
| |
CH3-C=C-CH3
|
H
Name: 2-butene
H H
| |
CH3-CH=C-CH3
|
H
Name: 1-butene
H
|
CH3-C=C-CH3
|
H
Name: Buta-1,3-diene
Step 6
A by-product of the reaction of butan-2-ol with concentrated sulfuric acid has the molecular formula C4H8O.
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By-product: The by-product of this reaction is likely to be butan-2-one (ketone).
Role of sulfuric acid: The sulfuric acid acts as a dehydrating agent, facilitating the formation of the ketone from the alcohol.
Name of separation method: The by-products could be separated via distillation.
Step 7
Give the observation you would make in this reaction.
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Observation with sodium chloride: The reaction would produce acidic fumes and the solid sodium chloride may dissolve or react leading to the formation of a color change in solution.
Step 8
State the role of the sulfuric acid.
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Role of sulfuric acid: The sulfuric acid serves as a catalyst in this reaction, aiding in the substitution of the chloride ion, while also providing acidic conditions.
Step 9
Identify the product responsible for each observation.
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Black solid: The black solid is likely due to carbon disulfide or iodine precipitate formation in the reaction with iodide.
Yellow solid: The yellow solid could be caused by the production of sulphur or iodine compounds.
Gas: The gas with the smell of bad eggs is likely hydrogen sulfide (H₂S), arising from the reaction of sulfuric acid with iodide.