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A two-step preparation of propylamine is shown - AQA - A-Level Chemistry - Question 30 - 2021 - Paper 3
Question 30
A two-step preparation of propylamine is shown. bromoethane → X → propylamine What is X? A CH₃CH₂CH₂NH₂ B CH₃CH₂CN C CH₃CH₂CH₂Br D CH₃CH₂NH₂
Worked Solution & Example Answer:A two-step preparation of propylamine is shown - AQA - A-Level Chemistry - Question 30 - 2021 - Paper 3
Step 1
What is X?
Answer
To determine what X is in the two-step preparation of propylamine, we need to analyze the structure of propylamine, which is CH₃CH₂CH₂NH₂. The reaction starts with bromoethane, which is CH₃CH₂Br.
In the first step, bromoethane (CH₃CH₂Br) must react to form X. The correct intermediate X before arriving at propylamine is CH₃CH₂CN, which can undergo subsequent conversion to propylamine. Thus, the compound X is
B CH₃CH₂CN.