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The equation for the reaction between ammonia and oxygen is shown - AQA - A-Level Chemistry - Question 3 - 2018 - Paper 1

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The equation for the reaction between ammonia and oxygen is shown. 4NH₃(g) + 5O₂(g) ⇌ 4NO(g) + 6H₂O(g) ΔH = -905 kJ mol⁻¹ Some standard entropies are given in Tabl... show full transcript

Worked Solution & Example Answer:The equation for the reaction between ammonia and oxygen is shown - AQA - A-Level Chemistry - Question 3 - 2018 - Paper 1

Step 1

Calculate the entropy change for the reaction between ammonia and oxygen.

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Answer

To calculate the entropy change ( ΔS ) for the reaction, we use the formula:

ΔS=S°productsS°reactantsΔS = S°_{products} - S°_{reactants}

For the given reaction:

  • Products: 4NO(g) + 6H₂O(g)
  • Reactants: 4NH₃(g) + 5O₂(g)

The standard entropies are:

  • S°(NO) = 211 J K⁻¹ mol⁻¹
  • S°(H₂O) = 189 J K⁻¹ mol⁻¹
  • S°(NH₃) = 193 J K⁻¹ mol⁻¹
  • S°(O₂) = 205 J K⁻¹ mol⁻¹

Calculating:

ΔS = egin{align*} & ext{(4 x 211) + (6 x 189)} \ & - ext{(4 x 193) + (5 x 205)} d \ & = 1978 - 1797 \ & = 181 ext{ J K}^{-1} ext{ mol}^{-1} egin{align*}$$

Step 2

Calculate a value for the Gibbs free-energy change (ΔG), in kJ mol⁻¹, for the reaction between ammonia and oxygen at 600 °C.

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Answer

To calculate ΔG, we use:

ΔG=ΔHTΔSΔG = ΔH - TΔS

Given:

  • ΔH = -905 kJ mol⁻¹
  • T = 600 °C = 873 K
  • ΔS = 181 J K⁻¹ mol⁻¹ = 0.181 kJ K⁻¹ mol⁻¹

Now substituting values:

ΔG=905873(0.181) =905158.553 =1063.553extkJmol1ΔG = -905 - 873(0.181) \ = -905 - 158.553 \ = -1063.553 ext{ kJ mol}^{-1}

Step 3

Explain how this change affects the value of ΔG for the reaction.

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Answer

As the temperature increases, the term TΔS grows larger, affecting ΔG. Since ΔG = ΔH - TΔS , an increase in temperature may result in a decrease in ΔG, making the reaction more thermodynamically favorable. In summary, ΔG becomes more negative as temperature increases, especially if ΔS greater than zero.

Step 4

Describe the stages of this alternative route.

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  1. Adsorption: Reactants (NH₃ and O₂) are adsorbed onto the platinum surface.
  2. Bond Breaking: Bonds between the nitrogen and hydrogen atoms in NH₃ and the O=O bond in O₂ begin to break.
  3. Reaction: The remaining atoms reorganize on the catalyst surface to form products (NO and H₂O).
  4. Desorption: Finally, the products (NO and H₂O) desorb from the surface, allowing the catalyst to be reused.

Step 5

Deduce the change in oxidation state of nitrogen, when NH₃ is oxidised to NO.

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Answer

In ammonia (NH₃), nitrogen has an oxidation state of -3. In nitrous oxide (NO), nitrogen has an oxidation state of +2. Therefore, the change in oxidation state is +5.

Step 6

Give an equation for this reaction.

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Answer

The balanced equation when ammonia reacts with oxygen to produce nitrous oxide (N₂O) is:

2NH3+2O2ightarrow2N2O+2H2O2NH₃ + 2O₂ ightarrow 2N₂O + 2H₂O

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