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A student is provided with 5.00 cm³ of 1.00 mol dm⁻³ ammonia solution - AQA - A-Level Chemistry - Question 30 - 2017 - Paper 3

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A student is provided with 5.00 cm³ of 1.00 mol dm⁻³ ammonia solution. The student was asked to prepare an ammonia solution with a concentration of 0.050 mol dm⁻³. ... show full transcript

Worked Solution & Example Answer:A student is provided with 5.00 cm³ of 1.00 mol dm⁻³ ammonia solution - AQA - A-Level Chemistry - Question 30 - 2017 - Paper 3

Step 1

Calculate the number of moles of ammonia in the initial solution

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Answer

Given that the concentration of the ammonia solution is 1.00 mol dm⁻³ and the volume is 5.00 cm³ (which is equivalent to 0.005 dm³), we can calculate the moles of ammonia using the formula:

moles=concentration×volume\text{moles} = \text{concentration} \times \text{volume}

Substituting the values:

moles=1.00 mol dm3×0.005 dm3=0.005 moles\text{moles} = 1.00 \text{ mol dm}^{-3} \times 0.005 \text{ dm}^3 = 0.005 \text{ moles}

Step 2

Determine the total volume required for the desired concentration

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Answer

To find the total volume needed to achieve a concentration of 0.050 mol dm⁻³ with 0.005 moles of ammonia, we can use the formula:

volume=molesconcentration\text{volume} = \frac{\text{moles}}{\text{concentration}}

Substituting the values:

volume=0.005 moles0.050 mol dm3=0.1 dm3=100 cm3\text{volume} = \frac{0.005 \text{ moles}}{0.050 \text{ mol dm}^{-3}} = 0.1 \text{ dm}^3 = 100 \text{ cm}^3

Step 3

Calculate the volume of water to be added

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Answer

The volume of water to be added is the difference between the total volume required and the initial volume of the ammonia solution:

volume of water=total volumeinitial volume\text{volume of water} = \text{total volume} - \text{initial volume}

Substituting the values:

volume of water=100 cm35.00 cm3=95.0 cm3\text{volume of water} = 100 \text{ cm}^3 - 5.00 \text{ cm}^3 = 95.0 \text{ cm}^3

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