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Some 1.0 mol dm<sup>-3</sup> solutions were mixed using equal volumes of each solution - AQA - A-Level Chemistry - Question 31 - 2018 - Paper 3

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Some 1.0 mol dm<sup>-3</sup> solutions were mixed using equal volumes of each solution. Which pair of solutions would give the greatest mass of solid? A. Ba(OH)<su... show full transcript

Worked Solution & Example Answer:Some 1.0 mol dm<sup>-3</sup> solutions were mixed using equal volumes of each solution - AQA - A-Level Chemistry - Question 31 - 2018 - Paper 3

Step 1

Which pair of solutions would give the greatest mass of solid?

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Answer

To determine which pair of solutions gives the greatest mass of solid when mixed, we consider the potential precipitate formed by the reaction of Ba(OH)<sub>2</sub> with sulfate ions from Na<sub>2</sub>SO<sub>4</sub>.

  1. Identify Potential Precipitate: Ba(OH)<sub>2</sub> dissociates into Ba<sup>2+</sup> and OH<sup>-</sup> ions. The sulfate ions (SO<sub>4</sub><sup>2-</sup>) from Na<sub>2</sub>SO<sub>4</sub> can react with Ba<sup>2+</sup> to precipitate barium sulfate (BaSO<sub>4</sub>), which is insoluble in water.

  2. Calculate the Products: The balanced equation for this reaction is: extBa(OH)2+extNa2extSO4extBaSO4(s)+2extNaOH ext{Ba(OH)}_2 + ext{Na}_2 ext{SO}_4 \rightarrow ext{BaSO}_4 (s) + 2 ext{NaOH} For every mole of Ba(OH)<sub>2</sub>, one mole of BaSO<sub>4</sub> is produced.

  3. Assessing Other Options:

    • A: Ba(OH)<sub>2</sub> + MgCl<sub>2</sub> does not produce BaSO<sub>4</sub>.
    • B: Ba(OH)<sub>2</sub> + MgSO<sub>4</sub> also produces Mg(OH)<sub>2</sub>, but not as much solid mass as BaSO<sub>4</sub>.
    • C: Ba(OH)<sub>2</sub> + NaCl produces no precipitate.
  4. Conclusion: D. Ba(OH)<sub>2</sub> and Na<sub>2</sub>SO<sub>4</sub> would yield the greatest mass of solid, due to the formation of BaSO<sub>4</sub>.

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