Cisplatin, [Pt(NH₃)₂Cl₂], is used as an anti-cancer drug - AQA - A-Level Chemistry - Question 4 - 2020 - Paper 3
Question 4
Cisplatin, [Pt(NH₃)₂Cl₂], is used as an anti-cancer drug.
Cisplatin works by causing the death of rapidly dividing cells.
Name the process that is prevented by cis... show full transcript
Worked Solution & Example Answer:Cisplatin, [Pt(NH₃)₂Cl₂], is used as an anti-cancer drug - AQA - A-Level Chemistry - Question 4 - 2020 - Paper 3
Step 1
Name the process that is prevented by cisplatin during cell division.
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Answer
The process that is prevented by cisplatin during cell division is DNA replication. Cisplatin interferes with the replicative machinery of rapidly dividing cells, thereby inhibiting their ability to divide and grow.
Step 2
Give the equation for this reaction.
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Answer
The equation for the formation of the complex ion B when cisplatin reacts with water can be represented as:
[Pt(NH3)2Cl2]+H2O→[Pt(NH3)2(H2O)]++Cl−
Step 3
Complete Figure 1 to show how the platinum complexes form a cross-link between the guanine nucleotides.
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Answer
In Figure 1, illustrate the cross-link by drawing a bond between the platinum ion from ion B and the nitrogen atoms in the two adjacent guanine nucleotides. Indicate the two connections indicating how the platinum forms a bridge between these nucleotides.
Step 4
Explain how graphical methods can be used to process the measured results, to confirm that the reaction is first order.
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Answer
To confirm that the reaction is first order, the concentration of cisplatin can be plotted against time. If the resulting graph is a straight line when the natural logarithm of the concentration is plotted against time, it indicates a first-order reaction. Additionally, the slope of this graph will correspond to the negative rate constant of the reaction.
Step 5
Complete Table 1.
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Fill in the missing values in Table 1 based on the provided calculations, ensuring that the values for ( \frac{1}{T} ) and ( \ln k ) are accurate.
Step 6
Calculate the activation energy, Eₐ, in kJ mol⁻¹.
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Answer
Using the Arrhenius equation and the plotted graph, calculate the activation energy. The gradient of the line in the Arrhenius plot provides (-Eₐ/R). Given the gradient from the graph, the activation energy can be derived as:
Ea=−Gradient×R
Given that the gas constant R is 8.31 J K⁻¹ mol⁻¹, convert the final value to kJ/mol for the answer.