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When $\theta$ is small, find an approximation for $\cos 30^\circ + \theta \sin 2\theta$, giving your answer in the form $a + b\theta^2$. - AQA - A-Level Maths Mechanics - Question 3 - 2017 - Paper 1

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When-$\theta$-is-small,-find-an-approximation-for-$\cos-30^\circ-+-\theta-\sin-2\theta$,-giving-your-answer-in-the-form-$a-+-b\theta^2$.-AQA-A-Level Maths Mechanics-Question 3-2017-Paper 1.png

When $\theta$ is small, find an approximation for $\cos 30^\circ + \theta \sin 2\theta$, giving your answer in the form $a + b\theta^2$.

Worked Solution & Example Answer:When $\theta$ is small, find an approximation for $\cos 30^\circ + \theta \sin 2\theta$, giving your answer in the form $a + b\theta^2$. - AQA - A-Level Maths Mechanics - Question 3 - 2017 - Paper 1

Step 1

Use approximations for trigonometric functions

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Answer

For small angles, we can use the approximations:

  • cosx1x22\cos x \approx 1 - \frac{x^2}{2}
  • sinxx\sin x \approx x
    Thus, for θ\theta, we approximate:
  • sin2θ2θ\sin 2\theta \approx 2\theta
  • cos30=32\cos 30^\circ = \frac{\sqrt{3}}{2} (exact, as 3030^\circ is not small).

Step 2

Substitute $2\theta$ and $30^\circ$ into the expression

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Answer

We can rewrite the expression as follows:
cos30+θsin2θ32+θ(2θ).\cos 30^\circ + \theta \sin 2\theta \approx \frac{\sqrt{3}}{2} + \theta(2\theta).
Thus, we have:
cos30+θsin2θ32+2θ2.\cos 30^\circ + \theta \sin 2\theta \approx \frac{\sqrt{3}}{2} + 2\theta^2.

Step 3

Obtain the correct answer in the form $a + b\theta^2$

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Answer

This expression simplifies to:
32+2θ2.\frac{\sqrt{3}}{2} + 2\theta^2.
In this case, a=32a = \frac{\sqrt{3}}{2} and b=2b = 2, therefore our final answer is in the required form.

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