Photo AI

The sum to infinity of a geometric series is 96 The first term of the series is less than 30 The second term of the series is 18 8 (a) Find the first term and common ratio of the series - AQA - A-Level Maths Mechanics - Question 8 - 2020 - Paper 3

Question icon

Question 8

The-sum-to-infinity-of-a-geometric-series-is-96-The-first-term-of-the-series-is-less-than-30-The-second-term-of-the-series-is-18--8-(a)-Find-the-first-term-and-common-ratio-of-the-series-AQA-A-Level Maths Mechanics-Question 8-2020-Paper 3.png

The sum to infinity of a geometric series is 96 The first term of the series is less than 30 The second term of the series is 18 8 (a) Find the first term and commo... show full transcript

Worked Solution & Example Answer:The sum to infinity of a geometric series is 96 The first term of the series is less than 30 The second term of the series is 18 8 (a) Find the first term and common ratio of the series - AQA - A-Level Maths Mechanics - Question 8 - 2020 - Paper 3

Step 1

Hence show that $\log_{3} u_n = n(1 - 2 \log_{2} 2) + 5 \log_{3} 2$

96%

114 rated

Answer

Starting from:

un=3n2n5u_n = \frac{3^{n}}{2^{n - 5}}

We apply the logarithmic identity:

logb(mn)=logbmlogbn\log_{b} \left( \frac{m}{n} \right) = \log_{b} m - \log_{b} n

Thus, we have:

log3un=log3(3n)log3(2n5)\log_{3} u_n = \log_{3} (3^{n}) - \log_{3} (2^{n - 5})

Calculating these logarithms:

=n(n5)log32= n - (n - 5) \log_{3} 2

This simplifies to:

=nnlog32+5log32= n - n \log_{3} 2 + 5 \log_{3} 2

Now we combine the terms:

=n(12log32)+5log32= n(1 - 2 \log_{3} 2) + 5 \log_{3} 2

Thus, we confirm:

log3un=n(12log22)+5log32\log_{3} u_n = n(1 - 2 \log_{2} 2) + 5 \log_{3} 2.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;