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The function $f$ is defined by $f(x) = e^{-x^4}, x \in \mathbb{R}$ Find $f^{-1}(x)$ and state its domain. - AQA - A-Level Maths Mechanics - Question 4 - 2018 - Paper 1

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The-function-$f$-is-defined-by-$f(x)-=-e^{-x^4},-x-\in-\mathbb{R}$--Find-$f^{-1}(x)$-and-state-its-domain.-AQA-A-Level Maths Mechanics-Question 4-2018-Paper 1.png

The function $f$ is defined by $f(x) = e^{-x^4}, x \in \mathbb{R}$ Find $f^{-1}(x)$ and state its domain.

Worked Solution & Example Answer:The function $f$ is defined by $f(x) = e^{-x^4}, x \in \mathbb{R}$ Find $f^{-1}(x)$ and state its domain. - AQA - A-Level Maths Mechanics - Question 4 - 2018 - Paper 1

Step 1

Take logs of an equation. Must be correct use of logs.

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Answer

Starting from the equation:

y=ex4y = e^{-x^4}

We take the natural logarithm of both sides:

ln(y)=x4\ln(y) = -x^4

Step 2

Obtain correct inverse function in any correct form.

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Answer

Rearranging gives:

ln(y)=x4-\ln(y) = x^4

From here, we take the fourth root:

x=ln(y)4x = \sqrt[4]{-\ln(y)}

Thus, the inverse function can be expressed as:

f1(x)=4+ln(x), for x>0f^{-1}(x) = 4 + \ln(x), \text{ for } x > 0

Step 3

Deduce correct domain.

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Answer

The domain of the inverse function f1(x)f^{-1}(x) is that xx must be positive:

x>0x > 0

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