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f(x) = 3x^2 Obtain $$ ext{lim}_{h o 0} \frac{f(x + h) - f(x)}{h}$$ Circle your answer. - AQA - A-Level Maths Mechanics - Question 3 - 2021 - Paper 3

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f(x)-=-3x^2--Obtain---$$-ext{lim}_{h--o-0}-\frac{f(x-+-h)---f(x)}{h}$$--Circle-your-answer.-AQA-A-Level Maths Mechanics-Question 3-2021-Paper 3.png

f(x) = 3x^2 Obtain $$ ext{lim}_{h o 0} \frac{f(x + h) - f(x)}{h}$$ Circle your answer.

Worked Solution & Example Answer:f(x) = 3x^2 Obtain $$ ext{lim}_{h o 0} \frac{f(x + h) - f(x)}{h}$$ Circle your answer. - AQA - A-Level Maths Mechanics - Question 3 - 2021 - Paper 3

Step 1

Obtain $$ ext{lim}_{h o 0} \frac{f(x + h) - f(x)}{h}$$

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Answer

To calculate the limit, we start by substituting the expression for f(x)f(x) into the limit definition:

  1. Calculate f(x+h)f(x + h): f(x+h)=3(x+h)2=3(x2+2xh+h2)=3x2+6xh+3h2f(x + h) = 3(x + h)^2 = 3(x^2 + 2xh + h^2) = 3x^2 + 6xh + 3h^2

  2. Substitute into the limit:

    f(x+h)f(x)h=(3x2+6xh+3h2)3x2h=6xh+3h2h\frac{f(x + h) - f(x)}{h} = \frac{(3x^2 + 6xh + 3h^2) - 3x^2}{h} = \frac{6xh + 3h^2}{h}

    Simplifying gives: 6x+3h6x + 3h

  3. Now, take the limit as hh approaches 0:

    limho0(6x+3h)=6x\text{lim}_{h o 0} (6x + 3h) = 6x

Thus, the final answer is:

6x6x

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