A number of forces act on a particle such that the resultant force is \( \begin{pmatrix} 6 \\ -3 \end{pmatrix} \) N - AQA - A-Level Maths Mechanics - Question 11 - 2020 - Paper 2

To find the total of the other forces acting on the particle, we can use the equation:

$\text{Resultant Force} = \text{Other Forces} + \text{Given Force}$

Rearranging gives:

$\text{Other Forces} = \text{Resultant Force} - \text{Given Force}$

Substituting the values:

$\text{Other Forces} = \begin{pmatrix} 6 \\ -3 \end{pmatrix} - \begin{pmatrix} 8 \\ -5 \end{pmatrix} = \begin{pmatrix} 6 - 8 \\ -3 + 5 \end{pmatrix} = \begin{pmatrix} -2 \\ 2 \end{pmatrix}$

Thus, the total of the other forces acting on the particle is ( \begin{pmatrix} -2 \ 2 \end{pmatrix} ) N.