Photo AI

A vehicle, of total mass 1200 kg, is travelling along a straight, horizontal road at a constant speed of 13 ms−1 - AQA - A-Level Maths Mechanics - Question 13 - 2021 - Paper 2

Question icon

Question 13

A-vehicle,-of-total-mass-1200-kg,-is-travelling-along-a-straight,-horizontal-road-at-a-constant-speed-of-13-ms−1-AQA-A-Level Maths Mechanics-Question 13-2021-Paper 2.png

A vehicle, of total mass 1200 kg, is travelling along a straight, horizontal road at a constant speed of 13 ms−1. This vehicle begins to accelerate at a constant ra... show full transcript

Worked Solution & Example Answer:A vehicle, of total mass 1200 kg, is travelling along a straight, horizontal road at a constant speed of 13 ms−1 - AQA - A-Level Maths Mechanics - Question 13 - 2021 - Paper 2

Step 1

Using the equation for constant acceleration

96%

114 rated

Answer

To find the acceleration, we can use the equation of motion:

v2=u2+2asv^2 = u^2 + 2as

Where:

  • v=17ms1v = 17 ms^{-1} (final speed)
  • u=13ms1u = 13 ms^{-1} (initial speed)
  • s=40ms = 40 m (distance travelled)

Substituting the values:

(17)2=(13)2+2a(40)(17)^2 = (13)^2 + 2a(40)

This simplifies to:

289=169+80a289 = 169 + 80a

Rearranging gives:

80a=28916980a = 289 - 169

Thus:

80a=12080a = 120

Therefore:

a = rac{120}{80} = 1.5 \, ms^{-2}

Step 2

Substituting into F = ma

99%

104 rated

Answer

To find the resultant force acting on the vehicle, we use Newton's second law:

F=maF = ma

Where:

  • m=1200kgm = 1200 kg (mass of the vehicle)
  • a=1.5ms2a = 1.5 ms^{-2} (acceleration)

Substituting the values:

F=1200imes1.5F = 1200 imes 1.5

Calculating this gives:

F=1800NF = 1800 \, N

Thus, the resultant force acting on the vehicle during the period of acceleration is 1800 N.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;