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A cyclist is towing a trailer behind her bicycle - AQA - A-Level Maths Pure - Question 15 - 2021 - Paper 2

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A cyclist is towing a trailer behind her bicycle. She is riding along a straight, horizontal path at a constant speed. A tension of $T$ newtons acts on the connect... show full transcript

Worked Solution & Example Answer:A cyclist is towing a trailer behind her bicycle - AQA - A-Level Maths Pure - Question 15 - 2021 - Paper 2

Step 1

State the value of $T$ giving a clear reason for your answer.

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Answer

To find the tension TT, we can analyze the forces acting on the trailer. Since the cyclist is moving at a constant speed, the forces acting on the trailer must be balanced. The force exerted by the cyclist is 40 N in the forward direction, while the resistance force acting against the trailer is 12 N.

Using the equilibrium condition:

Fnet=FdrivingFresistanceT=0F_{net} = F_{driving} - F_{resistance} - T = 0

This implies:

40extN12extNT=040 ext{ N} - 12 ext{ N} - T = 0

Thus, rearranging gives:

T=40extN12extN=28extNT = 40 ext{ N} - 12 ext{ N} = 28 ext{ N}

However, since the tension TT must also balance this resistance, the correct value for TT in equilibrium is:

T=12extNT = 12 ext{ N}

Step 2

State one valid assumption.

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Answer

One valid assumption that can be made in this scenario is that:

  • The rod remains horizontal.

Step 3

Form equilibrium equation of forces acting on cyclist and cycle.

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Answer

The forces acting on the cyclist and bicycle can be represented in equilibrium as:

  • Let RR be the total resistance against the forward force of the cyclist.

Since the cyclist achieves a balance of forces at constant speed,

40extN=T+R40 ext{ N} = T + R

Substituting T=12T = 12 N gives:

40=12+R40 = 12 + R

Thus,

R=4012=28extNR = 40 - 12 = 28 ext{ N}

The stated units are Newtons.

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