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Question 19
In this question use $g = 9.8 \, ext{ms}^{-2}$ A rough wooden ramp is 10 metres long and is inclined at an angle of 25° above the horizontal. The bottom of the ram... show full transcript
Step 1
Answer
To find the coefficient of friction, we first need to resolve the forces acting on the crate along the ramp and perpendicular to the ramp.
Resolve Weight: The weight of the crate can be resolved into two components:
Applying Newton's Second Law: The net force equation along the ramp can be written as: Where:
Thus, substituting into the equation:
Solve for : After substitution and simplification, we can find ( ext{μ} ) Rearranging to solve for ( ext{μ} ): This leads to an expression to calculate ( ext{μ} ) yielding ( ext{μ} , ext{≈} , 0.69 ).
Step 2
Answer
Using the kinematic equation for uniformly accelerated motion, where:
Substituting these values into the equation: = \frac{1}{2}(1.2)(14.44) \approx 8.664 , ext{m} $$ Therefore, the distance OA is approximately ( 10 , ext{m} - 8.664 , ext{m} = 1.336 , ext{m} ).
Step 3
Answer
One assumption made is that the crate is treated as a particle, meaning we neglect its dimensions and consider all its mass concentrated at a point. This simplifies the dynamics involved in the motion up the ramp.
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1.1 Proof
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1.2 Proof by Contradiction
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2.1 Laws of Indices & Surds
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2.2 Quadratics
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2.3 Simultaneous Equations
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2.4 Inequalities
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2.5 Polynomials
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2.6 Rational Expressions
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2.7 Graphs of Functions
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2.8 Functions
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2.9 Transformations of Functions
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2.10 Combinations of Transformations
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2.11 Partial Fractions
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2.12 Modelling with Functions
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2.13 Further Modelling with Functions
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3.2 Circles
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4.4 Geometric Sequences & Series
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5.6 Compound & Double Angle Formulae
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