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A vehicle, of total mass 1200 kg, is travelling along a straight, horizontal road at a constant speed of 13 m s⁻¹ - AQA - A-Level Maths Pure - Question 13 - 2021 - Paper 2

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A vehicle, of total mass 1200 kg, is travelling along a straight, horizontal road at a constant speed of 13 m s⁻¹. This vehicle begins to accelerate at a constant r... show full transcript

Worked Solution & Example Answer:A vehicle, of total mass 1200 kg, is travelling along a straight, horizontal road at a constant speed of 13 m s⁻¹ - AQA - A-Level Maths Pure - Question 13 - 2021 - Paper 2

Step 1

Selects and uses an appropriate constant acceleration equation to find the acceleration.

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Answer

To find the acceleration, we can apply the kinematic equation:

v2=u2+2asv^2 = u^2 + 2as

Where:

  • vv = final velocity = 17 m s⁻¹
  • uu = initial velocity = 13 m s⁻¹
  • ss = displacement = 40 m
  • aa = acceleration

Substituting in the values:

(17)2=(13)2+2a(40)(17)^2 = (13)^2 + 2a(40)

This simplifies to:

289=169+80a289 = 169 + 80a

Rearranging gives:

120=80a120 = 80a

Thus, we find:

a=1.5extms2a = 1.5 ext{ m s}^{-2}

Step 2

Substitutes their value of a into F = ma to obtain their F.

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Answer

Using Newton's second law to find the resultant force, we use the equation:

F=maF = ma

Where:

  • mm = mass = 1200 kg
  • aa = acceleration = 1.5 m s⁻²

Substituting the values:

F=1200imes1.5=1800extNF = 1200 imes 1.5 = 1800 ext{ N}

Therefore, the resultant force acting on the vehicle during the period of acceleration is 1800 N.

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