Sketch the region defined by the inequalities
y ≤ (1 − 2x)(x + 3) and y − x ≤ 3
Clearly indicate your region by shading it in and labelling it R. - AQA - A-Level Maths Pure - Question 4 - 2019 - Paper 3
Question 4
Sketch the region defined by the inequalities
y ≤ (1 − 2x)(x + 3) and y − x ≤ 3
Clearly indicate your region by shading it in and labelling it R.
Worked Solution & Example Answer:Sketch the region defined by the inequalities
y ≤ (1 − 2x)(x + 3) and y − x ≤ 3
Clearly indicate your region by shading it in and labelling it R. - AQA - A-Level Maths Pure - Question 4 - 2019 - Paper 3
Step 1
y ≤ (1 − 2x)(x + 3)
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Answer
Begin by determining the equation of the quadratic:
y=(1−2x)(x+3)
This expands to:
y=−2x2−5x+3
Identify the vertex and roots to sketch the curve:
The vertex occurs at the point where the derivative is zero.
Solve for x by using the vertex formula or completing the square.
For our parabola, the x-coordinate of the vertex can be found using
x=−2ab=−2(−2)−5=45
Calculate y at this x-value.
Determine the x-intercepts by solving:
0=−2x2−5x+3
Use the quadratic formula to find the roots.
Plot the curve with the correct orientation above the x-axis and label the vertex and intercepts.
Step 2
y − x ≤ 3
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Answer
Rearranging gives:
y≤x+3
This is a straight line with a slope of 1 and a y-intercept of 3.
Identify points on the line by substituting values for x:
For x = 0, y = 3 (point (0, 3))
For x = -3, y = 0 (point (-3, 0))
Sketch the line and shade the region below it since we need y less than or equal to the line.
Step 3
Shade the region R
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Answer
Identify the area of intersection between the parabola and the straight line.
Shade the regions that satisfy both inequalities:
Keep the area below the line y = x + 3.
Ensure the area remains below the quadratic curve as dictated by y ≤ (1 − 2x)(x + 3).