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4 (a) Use the factor theorem to prove that $x + 3$ is a factor of $p(x)$ Given the polynomial: $$ p(x) = 2x^3 + 7x^2 + 2x - 3 $$ To use the factor theorem, we need to evaluate $p(-3)$ and check if it equals 0. - AQA - A-Level Maths Pure - Question 4 - 2017 - Paper 1

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4-(a)-Use-the-factor-theorem-to-prove-that-$x-+-3$-is-a-factor-of-$p(x)$--Given-the-polynomial:--$$-p(x)-=-2x^3-+-7x^2-+-2x---3-$$--To-use-the-factor-theorem,-we-need-to-evaluate-$p(-3)$-and-check-if-it-equals-0.-AQA-A-Level Maths Pure-Question 4-2017-Paper 1.png

4 (a) Use the factor theorem to prove that $x + 3$ is a factor of $p(x)$ Given the polynomial: $$ p(x) = 2x^3 + 7x^2 + 2x - 3 $$ To use the factor theorem, we nee... show full transcript

Worked Solution & Example Answer:4 (a) Use the factor theorem to prove that $x + 3$ is a factor of $p(x)$ Given the polynomial: $$ p(x) = 2x^3 + 7x^2 + 2x - 3 $$ To use the factor theorem, we need to evaluate $p(-3)$ and check if it equals 0. - AQA - A-Level Maths Pure - Question 4 - 2017 - Paper 1

Step 1

Evaluate $p(-3)$

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Answer

Substituting x=3x = -3 into the polynomial:

p(3)=2(3)3+7(3)2+2(3)3p(-3) = 2(-3)^3 + 7(-3)^2 + 2(-3) - 3

Calculating each term:

  1. 2(3)3=2(27)=542(-3)^3 = 2(-27) = -54
  2. 7(3)2=7(9)=637(-3)^2 = 7(9) = 63
  3. 2(3)=62(-3) = -6
  4. 3=3-3 = -3

Combining these results:

p(3)=54+6363p(-3) = -54 + 63 - 6 - 3

Therefore:

p(3)=0p(-3) = 0

Since p(3)=0p(-3) = 0, by the factor theorem, x+3x + 3 is a factor of p(x)p(x).

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