Simplify fully
\(\frac{(x + 3)(6 - 2x)}{(x - 3)(3 + x)}\) for \(x \neq -3\)
Circle your answer,
−2 2 \(\frac{(6 - 2x)}{(x - 3)}\) \(\frac{(2x - 6)}{(x - 3)}\) - AQA - A-Level Maths Pure - Question 2 - 2021 - Paper 3

Question 2

Simplify fully
\(\frac{(x + 3)(6 - 2x)}{(x - 3)(3 + x)}\) for \(x \neq -3\)
Circle your answer,
−2 2 \(\frac{(6 - 2x)}{(x - 3)}\) \(\frac{(2x - 6)}{(x - 3)}\)
Worked Solution & Example Answer:Simplify fully
\(\frac{(x + 3)(6 - 2x)}{(x - 3)(3 + x)}\) for \(x \neq -3\)
Circle your answer,
−2 2 \(\frac{(6 - 2x)}{(x - 3)}\) \(\frac{(2x - 6)}{(x - 3)}\) - AQA - A-Level Maths Pure - Question 2 - 2021 - Paper 3
Step 1: Factor the Expression

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We begin by factoring the numerator ((x + 3)(6 - 2x)) and the denominator ((x - 3)(3 + x)).
Notice that (3 + x = x + 3), so we can rewrite it as:
[ \frac{(x + 3)(6 - 2x)}{(x - 3)(x + 3)} ]
Step 2: Cancel Common Factors

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Since ((x + 3)) appears in both the numerator and the denominator, we can cancel it out, provided that (x \neq -3).
This gives us:
[ \frac{(6 - 2x)}{(x - 3)} ]
Step 3: Final Simplification

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The simplified expression is thus:
[ \frac{(6 - 2x)}{(x - 3)} ]
Now, if we evaluate the expression by substituting (x = 3), we get an indeterminate form, reconfirming our cancellation was valid.
The answer is:
(-2) when evaluating alternative values.
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