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Simplify fully \(\frac{(x + 3)(6 - 2x)}{(x - 3)(3 + x)}\) for \(x \neq -3\) Circle your answer, −2 2 \(\frac{(6 - 2x)}{(x - 3)}\) \(\frac{(2x - 6)}{(x - 3)}\) - AQA - A-Level Maths Pure - Question 2 - 2021 - Paper 3

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Simplify-fully--\(\frac{(x-+-3)(6---2x)}{(x---3)(3-+-x)}\)-for-\(x-\neq--3\)--Circle-your-answer,--−2--2--\(\frac{(6---2x)}{(x---3)}\)--\(\frac{(2x---6)}{(x---3)}\)-AQA-A-Level Maths Pure-Question 2-2021-Paper 3.png

Simplify fully \(\frac{(x + 3)(6 - 2x)}{(x - 3)(3 + x)}\) for \(x \neq -3\) Circle your answer, −2 2 \(\frac{(6 - 2x)}{(x - 3)}\) \(\frac{(2x - 6)}{(x - 3)}\)

Worked Solution & Example Answer:Simplify fully \(\frac{(x + 3)(6 - 2x)}{(x - 3)(3 + x)}\) for \(x \neq -3\) Circle your answer, −2 2 \(\frac{(6 - 2x)}{(x - 3)}\) \(\frac{(2x - 6)}{(x - 3)}\) - AQA - A-Level Maths Pure - Question 2 - 2021 - Paper 3

Step 1

Step 1: Factor the Expression

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Answer

We begin by factoring the numerator ((x + 3)(6 - 2x)) and the denominator ((x - 3)(3 + x)).

Notice that (3 + x = x + 3), so we can rewrite it as:

[ \frac{(x + 3)(6 - 2x)}{(x - 3)(x + 3)} ]

Step 2

Step 2: Cancel Common Factors

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Answer

Since ((x + 3)) appears in both the numerator and the denominator, we can cancel it out, provided that (x \neq -3).

This gives us:

[ \frac{(6 - 2x)}{(x - 3)} ]

Step 3

Step 3: Final Simplification

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Answer

The simplified expression is thus:

[ \frac{(6 - 2x)}{(x - 3)} ]

Now, if we evaluate the expression by substituting (x = 3), we get an indeterminate form, reconfirming our cancellation was valid.

The answer is:

(-2) when evaluating alternative values.

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