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The function $f$ is defined by $f(x) = e^{-x^4}, x \in \mathbb{R}$ - AQA - A-Level Maths Pure - Question 4 - 2018 - Paper 1

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The function $f$ is defined by $f(x) = e^{-x^4}, x \in \mathbb{R}$. Find $f^{-1}(x)$ and state its domain.

Worked Solution & Example Answer:The function $f$ is defined by $f(x) = e^{-x^4}, x \in \mathbb{R}$ - AQA - A-Level Maths Pure - Question 4 - 2018 - Paper 1

Step 1

Find $f^{-1}(x)$

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Answer

To find the inverse of the function, we start with the equation:

y=ex4y = e^{-x^4}

Taking the natural logarithm on both sides gives:

ln(y)=x4\ln(y) = -x^4

Rearranging this equation leads to:

ln(y)=x4-\ln(y) = x^4

And therefore:

x=ln(y)4x = \sqrt[4]{-\ln(y)}

Thus, the inverse function can be expressed as:

$$f^{-1}(x) = 4 + \ln(x), \text{ for } x > 0.$

Step 2

State its domain

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Answer

For the inverse function f1(x)=4+ln(x)f^{-1}(x) = 4 + \ln(x), the domain is determined by the condition under which the logarithm is defined. Since ln(x)\ln(x) is only defined for x>0x > 0, the domain of the inverse function is:

Domain: x>0x > 0.

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