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A periodic sequence is defined by $U_n = ext{sin}\left(\frac{n \pi}{2}\right)$ State the period of this sequence - AQA - A-Level Maths: Pure - Question 3 - 2018 - Paper 1

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A periodic sequence is defined by $U_n = ext{sin}\left(\frac{n \pi}{2}\right)$ State the period of this sequence. Circle your answer. 8 2π 4 π

Worked Solution & Example Answer:A periodic sequence is defined by $U_n = ext{sin}\left(\frac{n \pi}{2}\right)$ State the period of this sequence - AQA - A-Level Maths: Pure - Question 3 - 2018 - Paper 1

Step 1

State the period of this sequence.

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Answer

The period of the sine function is typically defined as 2π2\pi. However, since the function includes a coefficient in front of nn, we need to adjust the period accordingly. Here, the argument of the sine function is nπ2\frac{n \pi}{2}, indicating that the input to sine completes one full cycle when:

nπ2=2π\frac{n \pi}{2} = 2\pi

Solving for nn gives:

n=2π2π=4n = \frac{2\pi \cdot 2}{\pi} = 4

Thus, the period of the sequence UnU_n is 4.

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