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Determine a sequence of transformations which maps the graph of y = cos θ onto the graph of y = 3cos θ + 3sin θ Fully justify your answer. - AQA - A-Level Maths Pure - Question 5 - 2017 - Paper 2

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Determine a sequence of transformations which maps the graph of y = cos θ onto the graph of y = 3cos θ + 3sin θ Fully justify your answer.

Worked Solution & Example Answer:Determine a sequence of transformations which maps the graph of y = cos θ onto the graph of y = 3cos θ + 3sin θ Fully justify your answer. - AQA - A-Level Maths Pure - Question 5 - 2017 - Paper 2

Step 1

Identify the transformations needed to map $y = \cos \theta$ to $y = 3\cos \theta + 3\sin \theta$

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Answer

The graph can be rewritten in the form of Rcos(θα)R \cos(\theta - \alpha), where R is the amplitude and \alpha is the phase shift. Therefore, we compare:

y=3cosθ+3sinθy = 3\cos \theta + 3\sin \theta

with Rcos(θα)R\cos(\theta - \alpha).

This gives us:

Rcosα=3andRsinα=3R\cos \alpha = 3 \quad \text{and} \quad R\sin \alpha = 3.

Step 2

Calculate R and α

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Answer

To find R, we use:

R=(3)2+(3)2=18=32R = \sqrt{(3)^2 + (3)^2} = \sqrt{18} = 3\sqrt{2}.

Next, we find \alpha:

\sin \alpha = \frac{3}{R} = \frac{3}{3\sqrt{2}} = \frac{1}{\sqrt{2}}$$. This gives us \alpha = \frac{\pi}{4}$.

Step 3

Interpret the transformations

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Answer

The transformation involves:

  1. Stretch in the y-direction by a factor of 323\sqrt{2}, hence:

y=32cos(θ)y = 3\sqrt{2}\cos(\theta).

  1. Phase shift / translation to the right by \frac{\pi}{4}.

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