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Which one of these functions is decreasing for all real values of x? Circle your answer - AQA - A-Level Maths: Pure - Question 1 - 2020 - Paper 2

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Which one of these functions is decreasing for all real values of x? Circle your answer. f(x) = e^x f(x) = -e^{1-x} f(x) = -e^{x-1} f(x) = -e^{-x}

Worked Solution & Example Answer:Which one of these functions is decreasing for all real values of x? Circle your answer - AQA - A-Level Maths: Pure - Question 1 - 2020 - Paper 2

Step 1

Identify which function is decreasing

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Answer

To determine which function is decreasing for all real values of xx, we can analyze the derivatives of the given functions:

  1. For f(x)=exf(x) = e^x, the derivative is f′(x)=exf'(x) = e^x, which is always positive. Thus, this function is increasing.

  2. For f(x)=−e1−xf(x) = -e^{1-x}, the derivative is: f′(x)=−(−e1−x)(−1)=e1−xf'(x) = -(-e^{1-x})(-1) = e^{1-x} This is also always positive, indicating the function is increasing.

  3. For f(x)=−ex−1f(x) = -e^{x-1}, the derivative is: f′(x)=−ex−1f'(x) = -e^{x-1} This is always negative, indicating that this function is decreasing.

  4. For f(x)=−e−xf(x) = -e^{-x}, the derivative is: f′(x)=−(−e−x)(−1)=e−xf'(x) = -(-e^{-x})(-1) = e^{-x} This is also positive, indicating that this function is increasing.

Based on the analysis, the function that is decreasing for all real values of xx is:

f(x)=−ex−1f(x) = -e^{x-1}.

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