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Given $y = e^{kx}$, where $k$ is a constant, find \( rac{dy}{dx}\) - AQA - A-Level Maths Pure - Question 2 - 2019 - Paper 1

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Given-$y-=-e^{kx}$,-where-$k$-is-a-constant,-find-\(-rac{dy}{dx}\)-AQA-A-Level Maths Pure-Question 2-2019-Paper 1.png

Given $y = e^{kx}$, where $k$ is a constant, find \( rac{dy}{dx}\). Circle your answer.

Worked Solution & Example Answer:Given $y = e^{kx}$, where $k$ is a constant, find \( rac{dy}{dx}\) - AQA - A-Level Maths Pure - Question 2 - 2019 - Paper 1

Step 1

Find \(\frac{dy}{dx}\)

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Answer

To differentiate the function (y = e^{kx}) with respect to (x), we use the chain rule. The derivative of (e^{u}) is (e^{u} \cdot \frac{du}{dx}), where (u = kx). Hence:

dydx=ekxd(kx)dx\frac{dy}{dx} = e^{kx} \cdot \frac{d(kx)}{dx}

Since (\frac{d(kx)}{dx} = k), we can substitute this back:

dydx=kekx\frac{dy}{dx} = k e^{kx}

Thus, the correct answer to circle is (\frac{dy}{dx} = ke^{kx}).

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