Show that the solution of the equation
$$5^x = 3^{x+4}$$
can be written as
$$x = \frac{\ln 81}{\ln 5 - \ln 3}$$
Fully justify your answer. - AQA - A-Level Maths Pure - Question 6 - 2021 - Paper 2
Question 6
Show that the solution of the equation
$$5^x = 3^{x+4}$$
can be written as
$$x = \frac{\ln 81}{\ln 5 - \ln 3}$$
Fully justify your answer.
Worked Solution & Example Answer:Show that the solution of the equation
$$5^x = 3^{x+4}$$
can be written as
$$x = \frac{\ln 81}{\ln 5 - \ln 3}$$
Fully justify your answer. - AQA - A-Level Maths Pure - Question 6 - 2021 - Paper 2
Step 1
Taking Logarithms on Both Sides
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Answer
To solve the equation, we start by taking the natural logarithm of both sides:
ln(5x)=ln(3x+4)
Using the logarithm power rule, this simplifies to:
xln5=(x+4)ln3
Step 2
Rearranging the Equation
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Answer
Next, we can expand the right side:
xln5=xln3+4ln3
Now, we'll isolate the terms involving x:
xln5−xln3=4ln3
Step 3
Factoring Out x
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Answer
Factoring x out from the left-hand side, we have:
x(ln5−ln3)=4ln3
Step 4
Final Expression for x
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Answer
Finally, we solve for x:
x=ln5−ln34ln3
To express this in the form required, we recognize that: