Theresa bought a house on 2 January 1970 for £8000 - AQA - A-Level Maths Pure - Question 8 - 2019 - Paper 2
Question 8
Theresa bought a house on 2 January 1970 for £8000.
The house was valued by a local estate agent on the same date every 10 years up to 2010.
The valuations are sho... show full transcript
Worked Solution & Example Answer:Theresa bought a house on 2 January 1970 for £8000 - AQA - A-Level Maths Pure - Question 8 - 2019 - Paper 2
Step 1
Show that $V = pq$ can be written as $ ext{log}_{10} V = ext{log}_{10} p + ext{log}_{10} q$
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Answer
To manipulate the equation V=pq, we first take the logarithm (base 10) of both sides:
Starting with the equation:
V=pq
Apply the logarithm:
extlog10V=extlog10(pq)
Using the property of logarithms that states extlog10(ab)=extlog10a+extlog10b, we can rewrite the equation:
extlog10V=extlog10p+extlog10q
Thus, we have shown that V=pq can indeed be expressed as extlog10V=extlog10p+extlog10q.
Step 2
The values in the table of log$_{10} V$ against t have been plotted and a line of best fit has been drawn on the graph below.
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Answer
From the graph, we can analyze the trend of the data points plotted:
Identify points: The plotted data points (t,extlog10V) correspond to the following pairs:
(0, 3.90)
(10, 4.28)
(20, 4.63)
(30, 4.91)
(40, 5.31)
Calculate the slope (gradient) of the line of best fit:
Using two points, for example, (0, 3.90) and (40, 5.31):
Considering logarithmic relationships, we can establish the equation for the line of best fit. If the line follows the form of y=mx+b (where m is the slope and b is the y-intercept), we can deduce the values accordingly and derive constants p and q for further calculations.