Photo AI

Given that $a > 0$, determine which of these expressions is not equivalent to the others - AQA - A-Level Maths Pure - Question 1 - 2019 - Paper 1

Question icon

Question 1

Given-that-$a->-0$,-determine-which-of-these-expressions-is-not-equivalent-to-the-others-AQA-A-Level Maths Pure-Question 1-2019-Paper 1.png

Given that $a > 0$, determine which of these expressions is not equivalent to the others. Circle your answer. −2log₁₀(1/a) 2log₁₀(a) log₁₀(a²) −4log₁₀(√a)

Worked Solution & Example Answer:Given that $a > 0$, determine which of these expressions is not equivalent to the others - AQA - A-Level Maths Pure - Question 1 - 2019 - Paper 1

Step 1

Determine the equivalent expressions: −2log₁₀(1/a)

96%

114 rated

Answer

Using the property of logarithms, we have:

2log10(1/a)=2(log10(a1))=2(log10(a))=2log10(a)−2log₁₀(1/a) = −2(log₁₀(a^{-1})) = −2(−log₁₀(a)) = 2log₁₀(a)

This shows that (−2log₁₀(1/a)) is equivalent to (2log₁₀(a)).

Step 2

Determine the equivalent expressions: log₁₀(a²)

99%

104 rated

Answer

Using the power rule of logarithms:

log10(a2)=2log10(a)log₁₀(a²) = 2log₁₀(a)

This indicates that (log₁₀(a²)) is also equivalent to (2log₁₀(a)).

Step 3

Determine the equivalent expressions: −4log₁₀(√a)

96%

101 rated

Answer

Using the logarithmic property for square roots, we have:

−4log₁₀(√a) = −4log₁₀(a^{1/2}) = −4× rac{1}{2}log₁₀(a) = −2log₁₀(a)

This implies that (−4log₁₀(√a)) is equivalent to (−2log₁₀(a)).

Step 4

Conclusion: Identify the expression that is not equivalent

98%

120 rated

Answer

Thus, the only expression that does not match with others is:

4log10(a)−4log₁₀(√a)

Therefore, the answer to circle is (−4log₁₀(√a)).

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;