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The number of radioactive atoms, $N$, in a sample of a sodium isotope after time $t$ hours can be modelled by $$N = N_0 e^{-kt}$$ where $N_0$ is the initial number of radioactive atoms in the sample and $k$ is a positive constant - AQA - A-Level Maths Pure - Question 5 - 2020 - Paper 3

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The-number-of-radioactive-atoms,-$N$,-in-a-sample-of-a-sodium-isotope-after-time-$t$-hours-can-be-modelled-by--$$N-=-N_0-e^{-kt}$$--where-$N_0$-is-the-initial-number-of-radioactive-atoms-in-the-sample-and-$k$-is-a-positive-constant-AQA-A-Level Maths Pure-Question 5-2020-Paper 3.png

The number of radioactive atoms, $N$, in a sample of a sodium isotope after time $t$ hours can be modelled by $$N = N_0 e^{-kt}$$ where $N_0$ is the initial number... show full transcript

Worked Solution & Example Answer:The number of radioactive atoms, $N$, in a sample of a sodium isotope after time $t$ hours can be modelled by $$N = N_0 e^{-kt}$$ where $N_0$ is the initial number of radioactive atoms in the sample and $k$ is a positive constant - AQA - A-Level Maths Pure - Question 5 - 2020 - Paper 3

Step 1

Substitutes $t = 15.9$ hours and $N = \frac{N_0}{2}$ in the model to find $k$

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Answer

Using the model: N02=N0ek15.9\frac{N_0}{2} = N_0 e^{-k \cdot 15.9} Dividing both sides by N0N_0 (assuming N0>0N_0 > 0) gives: 12=ek15.9\frac{1}{2} = e^{-k \cdot 15.9} Taking the natural logarithm: k15.9=ln(12)-k \cdot 15.9 = \ln\left(\frac{1}{2}\right) Thus, k=ln(0.5)15.9k = \frac{-\ln(0.5)}{15.9} Calculating yields: k0.0436k \approx 0.0436

Step 2

Substitutes their value of $k$ and $N = 0.1N_0$ in the model to find $t$

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Answer

Using: 0.1N0=N0e0.0436t0.1N_0 = N_0 e^{-0.0436t} Dividing both sides by N0N_0 gives: 0.1=e0.0436t0.1 = e^{-0.0436t} Taking the natural logarithm: 0.0436t=ln(0.1)-0.0436t = \ln(0.1) Thus, t=ln(0.1)0.0436t = \frac{-\ln(0.1)}{0.0436} Calculating this results in: t52.3 hourst \approx 52.3 \text{ hours} Converting hours to days: 52.3242.18 days2.2 days (to 2 decimal places)\frac{52.3}{24} \approx 2.18 \text{ days} \Rightarrow 2.2 \text{ days (to 2 decimal places)}

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