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f(x) = 3x² Obtain $$ ext{lim}_{h o 0} \frac{f(x + h) - f(x)}{h}$$ Circle your answer. - AQA - A-Level Maths Pure - Question 3 - 2021 - Paper 3

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f(x)-=-3x²--Obtain--$$-ext{lim}_{h--o-0}-\frac{f(x-+-h)---f(x)}{h}$$--Circle-your-answer.-AQA-A-Level Maths Pure-Question 3-2021-Paper 3.png

f(x) = 3x² Obtain $$ ext{lim}_{h o 0} \frac{f(x + h) - f(x)}{h}$$ Circle your answer.

Worked Solution & Example Answer:f(x) = 3x² Obtain $$ ext{lim}_{h o 0} \frac{f(x + h) - f(x)}{h}$$ Circle your answer. - AQA - A-Level Maths Pure - Question 3 - 2021 - Paper 3

Step 1

Obtain $$\text{lim}_{h \to 0} \frac{f(x + h) - f(x)}{h}$$

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Answer

To find the limit, we first need to calculate (f(x + h)):

  1. Substitute (x + h) into the function: [f(x + h) = 3(x + h)^2 = 3(x^2 + 2xh + h^2) = 3x^2 + 6xh + 3h^2]

  2. Now, calculate (f(x + h) - f(x)): [f(x + h) - f(x) = (3x^2 + 6xh + 3h^2) - 3x^2 = 6xh + 3h^2]

  3. Substitute this result into the limit expression: [\frac{f(x+h) - f(x)}{h} = \frac{6xh + 3h^2}{h} = 6x + 3h]

  4. Take the limit as (h) approaches 0: [\text{lim}_{h \to 0} (6x + 3h) = 6x]

Thus, the final answer is (6x).

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