Photo AI

7 (a) Sketch the graph of any cubic function that has both three distinct real roots and a positive coefficient of $x^3$ - AQA - A-Level Maths Pure - Question 7 - 2019 - Paper 2

Question icon

Question 7

7-(a)-Sketch-the-graph-of-any-cubic-function-that-has-both-three-distinct-real-roots-and-a-positive-coefficient-of-$x^3$-AQA-A-Level Maths Pure-Question 7-2019-Paper 2.png

7 (a) Sketch the graph of any cubic function that has both three distinct real roots and a positive coefficient of $x^3$. 7 (b) The function $f(x)$ is defined by ... show full transcript

Worked Solution & Example Answer:7 (a) Sketch the graph of any cubic function that has both three distinct real roots and a positive coefficient of $x^3$ - AQA - A-Level Maths Pure - Question 7 - 2019 - Paper 2

Step 1

Sketch the graph of any cubic function that has both three distinct real roots and a positive coefficient of $x^3$.

96%

114 rated

Answer

To sketch the graph of a cubic function with three distinct real roots, we can take a generic form of the function, such as:

f(x)=(xr1)(xr2)(xr3)f(x) = (x - r_1)(x - r_2)(x - r_3)

where r1r_1, r2r_2, and r3r_3 are the three distinct real roots. Since we want the leading coefficient to be positive, we ensure that f(x)f(x) opens upwards. For example, choosing r1=2r_1 = -2, r2=0r_2 = 0, and r3=1r_3 = 1 gives:

f(x)=(x+2)(x)(x1)=x3+x22xf(x) = (x + 2)(x)(x - 1) = x^3 + x^2 - 2x

The sketch will show the curve crossing the xx-axis at x=2x = -2, x=0x = 0, and x=1x = 1, thus confirming three distinct real roots.

Step 2

Show that there is a turning point where the curve crosses the $y$-axis.

99%

104 rated

Answer

First, we differentiate the function:

f(x)=3x2+6pxf'(x) = 3x^2 + 6px

Setting this equal to zero for turning points:

3x(x + 2p) = 0$$ This gives: 1. $x = 0$ 2. $x = -2p$ Since $p > 0$, $-2p < 0$. Therefore, $x = 0$ is indeed a turning point where the curve crosses the $y$-axis, which confirms the presence of a turning point at the $y$-axis.

Step 3

The equation $f(x) = 0$ has three distinct real roots. By considering the positions of the turning points, find, in terms of $p$, the range of possible values of $q$.

96%

101 rated

Answer

We have already defined the turning points as x=0x = 0 and x=2px = -2p. To have three distinct real roots, we require:

  1. The turning point at x=2px = -2p must be a local maximum, and therefore:
    • f(2p)f(-2p) should be positive, and f(0)f(0) must be negative for a change in sign (indicating distinct roots).

Calculating:

  • f(0)=qf(0) = q
  • f(2p)=(2p)3+3p(2p)2+q=8p3+12p3+q=4p3+qf(-2p) = (-2p)^3 + 3p(-2p)^2 + q = -8p^3 + 12p^3 + q = 4p^3 + q

Thus, we must have:

f(0)<0extandf(2p)>0f(0) < 0 ext{ and } f(-2p) > 0
which leads to:

q<0extand4p3+q>0q < 0 ext{ and } 4p^3 + q > 0
or 4p3<q<0-4p^3 < q < 0

This provides the range of possible values for qq in terms of pp.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;