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Given that $$\int_0^{10} f(x) \,dx = 7$$ deduce the value of $$\int_0^{10} (f(x) + 1) \,dx$$ Circle your answer. - AQA - A-Level Maths Pure - Question 1 - 2020 - Paper 3

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Given-that-$$\int_0^{10}-f(x)-\,dx-=-7$$-deduce-the-value-of-$$\int_0^{10}-(f(x)-+-1)-\,dx$$-Circle-your-answer.-AQA-A-Level Maths Pure-Question 1-2020-Paper 3.png

Given that $$\int_0^{10} f(x) \,dx = 7$$ deduce the value of $$\int_0^{10} (f(x) + 1) \,dx$$ Circle your answer.

Worked Solution & Example Answer:Given that $$\int_0^{10} f(x) \,dx = 7$$ deduce the value of $$\int_0^{10} (f(x) + 1) \,dx$$ Circle your answer. - AQA - A-Level Maths Pure - Question 1 - 2020 - Paper 3

Step 1

deduce the value of $$\int_0^{10} (f(x) + 1) \,dx$$

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Answer

To deduce the value of the integral 010(f(x)+1)dx\int_0^{10} (f(x) + 1) \,dx, we can use the properties of integrals:

  1. Break down the integral: We can express the integral as: 010(f(x)+1)dx=010f(x)dx+0101dx\int_0^{10} (f(x) + 1) \,dx = \int_0^{10} f(x) \,dx + \int_0^{10} 1 \,dx

  2. Evaluate the first part: From the information given, we have: 010f(x)dx=7\int_0^{10} f(x) \,dx = 7

  3. Evaluate the second part: The integral of 1 over the interval from 0 to 10 is simply the length of the interval: 0101dx=100=10\int_0^{10} 1 \,dx = 10 - 0 = 10

  4. Combine the results: Now we combine the two results: 010(f(x)+1)dx=7+10=17\int_0^{10} (f(x) + 1) \,dx = 7 + 10 = 17

Thus, the value of the integral is 17. Therefore, the correct answer is 17.

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