Mass spectrometers are used to measure the masses of ions - AQA - A-Level Physics - Question 3 - 2020 - Paper 2
Question 3
Mass spectrometers are used to measure the masses of ions.
Figure 3 shows one part of a mass spectrometer.
A narrow beam consists of positive lithium ions travellin... show full transcript
Worked Solution & Example Answer:Mass spectrometers are used to measure the masses of ions - AQA - A-Level Physics - Question 3 - 2020 - Paper 2
Step 1
Draw two labelled arrows on Figure 3 to show the directions of the electric force F_E and the magnetic force F_M acting on A.
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Answer
Draw an arrow pointing up to represent the electric force F_E acting on the positive lithium ion A due to the electric field E.
Draw an arrow pointing downwards to represent the magnetic force F_M acting on the ion, which is in the direction according to the right-hand rule.
Step 2
Calculate E.
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Answer
Using the relationship for equilibrium of forces:
FE=FM
Where:
Electric force, FE=qE
Magnetic force, FM=qvB
Setting them equal gives:
qE=qvB
Solving for E, we have:
E=vB
Substituting the known values:
v=1.5×105 m s−1
B=0.12 T
Thus,
E=(1.5×105)×(0.12)=1.8×104V/m
Step 3
Show that the radius r of the circular path is given by r = mv/Bq.
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Answer
In a uniform magnetic field, the centripetal force needed for circular motion is provided by the magnetic force:
Fc=FM
Where:
Centripetal force, Fc=rmv2
Magnetic force, FM=qvB
Setting these equal gives:
rmv2=qvB
Rearranging for r:
r=qBmv
This shows that the radius r is directly proportional to mass m and inversely proportional to charge q and magnetic field B.
Step 4
Calculate the distance between the small aperture and the point where this ion strikes the detector surface.
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Answer
Using the formula for radius of the path:
r=qBmv
Substituting known values:
v=1.5×105 m s−1
B=0.12 T
Mass of 6Li+ ion = 1.0×10−26 kg
Charge of 6Li+ ion, q=1.6×10−19 C
Calculating r:
r=(1.6×10−19)(0.12)(1.0×10−26)(1.5×105)
After calculations, find the distance from small aperture to detector surface.
Step 5
Determine the speed of the ion when it emerges through aperture P.
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Answer
Using energy conservation, the work done by the electric field equals the gain in kinetic energy:
qEd=21mv2
Where:
d = distance between electrodes = 3000 V
Charge of ion, q=1.2×10−19 C
Mass of ion = 1.2×10−26 kg
To find v, solve for speed:
v=m2qEd
Substituting the values:
E=6000V
d=3000V
Thus,
v is determined after performing calculations.
Step 6
Discuss how the masses of the ions can be deduced from the measurement of these time intervals.
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Answer
The time taken for ions to travel from aperture P to the detector relates closely to their mass and charge due to their varying accelerations. The ions of different masses will have different speeds and consequently take different times.
The relationship can be described by:
t=vl
Where t is the time interval, l is distance traveled, and v is speed derived from mass and charge. Therefore, by measuring these time intervals, we can deduce the mass of the ions as the time intervals will differ according to the equation relating mass, charge, and speed.