Determine whether the following reaction is a possible decay for the neutral pion $ ext{p}^0$ - AQA - A-Level Physics - Question 1 - 2020 - Paper 1
Question 1
Determine whether the following reaction is a possible decay for the neutral pion $ ext{p}^0$.
$ ext{p}^0 o e^+ + ext{mu}^+ + ar{
u}_e$
State the two possible q... show full transcript
Worked Solution & Example Answer:Determine whether the following reaction is a possible decay for the neutral pion $ ext{p}^0$ - AQA - A-Level Physics - Question 1 - 2020 - Paper 1
Step 1
Determine whether the following reaction is a possible decay for the neutral pion $ ext{p}^0$
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To determine if the decay can occur, we need to check if lepton number conservation is maintained. In the reaction
u}_e,$$
we have:
- Initial lepton number: 0 (neutral pion)
- Final lepton number: +1 (positron) + 1 (anti-muon neutrino) - 1 (muon) = +1.
Since the lepton number is not conserved (initial is 0 and final is +1), this decay is not possible.
Step 2
State the two possible quark configurations of a $ ext{p}^0$
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The neutral pion extp0 can have the following quark configurations:
Up quark and down quark: uar{u}
Down quark and up quark: dar{d}
Step 3
Discuss whether this suggestion is correct.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The claim that the kaon extK0 and the anti-kaon ar{ ext{K}}^0 are the same particle is incorrect. The kaon extK0 has the quark content dar{s} (down quark and anti-strange quark), while the anti-kaon ar{ ext{K}}^0 is composed of sar{d} (strange quark and anti-down quark). They are distinct particles due to their differing quark content and properties such as strangeness.
Step 4
Discuss whether a kaon, a muon and a pion each have the properties of the predicted particle.
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To analyze the properties:
Kaon (extK): Its rest energy is approximately 497.762 MeV, which falls between that of an electron (0.511 MeV) and a nucleon (~938 MeV). Thus, it could exhibit the predicted properties.
Muon (extμ): Its rest energy is about 105.658 MeV, also fitting the criteria to be the predicted particle.
Pion (extπ): With a rest energy of about 139.570 MeV, it too falls within the required range.
Hence, all three particles (kaon, muon, and pion) share properties consistent with the predicted particle.