Photo AI

A pair of cameras is used on a motorway to help determine the average speed of vehicles travelling between the two cameras - AQA - A-Level Physics - Question 4 - 2020 - Paper 1

Question icon

Question 4

A-pair-of-cameras-is-used-on-a-motorway-to-help-determine-the-average-speed-of-vehicles-travelling-between-the-two-cameras-AQA-A-Level Physics-Question 4-2020-Paper 1.png

A pair of cameras is used on a motorway to help determine the average speed of vehicles travelling between the two cameras. Figure 5 shows the speed–time graph for... show full transcript

Worked Solution & Example Answer:A pair of cameras is used on a motorway to help determine the average speed of vehicles travelling between the two cameras - AQA - A-Level Physics - Question 4 - 2020 - Paper 1

Step 1

Determine whether the average speed of the car exceeded this speed limit.

96%

114 rated

Answer

To find the average speed of the car, we calculate the area under the speed–time graph shown in Figure 5. The graph is composed of three segments:

  1. A triangle (0 to 1 minutes) with base 1 minute and height 15 m s⁻¹, yielding an area of:

    Area=12×base×height=12×1×15=7.5 m\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 1 \times 15 = 7.5 \text{ m}

  2. A rectangle (1 to 2.5 minutes) with width 1.5 minutes and height 25 m s⁻¹, yielding an area of:

    Area=width×height=1.5×25=37.5 m\text{Area} = \text{width} \times \text{height} = 1.5 \times 25 = 37.5 \text{ m}

  3. A triangle (2.5 to 4 minutes) with base 1.5 minutes and height 25 m s⁻¹, yielding an area of:

    Area=12×1.5×25=18.75 m\text{Area} = \frac{1}{2} \times 1.5 \times 25 = 18.75 \text{ m}

Adding these areas together, the total distance travelled is: Total distance=7.5+37.5+18.75=63.75 m\text{Total distance} = 7.5 + 37.5 + 18.75 = 63.75 \text{ m}

To find the average speed, we divide the total distance by the total time (4 minutes): Average speed=63.75 m4 min=63.75 m240 s=0.26562 m s1\text{Average speed} = \frac{63.75 \text{ m}}{4 \text{ min}} = \frac{63.75 \text{ m}}{240 \text{ s}} = 0.26562 \text{ m s}^{-1}

Since 0.26562 m s⁻¹ is less than 22 m s⁻¹, we conclude that the average speed of the car did not exceed the speed limit.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;