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Figure 2 shows the distribution of kinetic energies of β- particles from the decay of carbon-14 - AQA - A-Level Physics - Question 2 - 2022 - Paper 1

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Figure 2 shows the distribution of kinetic energies of β- particles from the decay of carbon-14. Explain how Figure 2 supports the existence of the antineutrino. T... show full transcript

Worked Solution & Example Answer:Figure 2 shows the distribution of kinetic energies of β- particles from the decay of carbon-14 - AQA - A-Level Physics - Question 2 - 2022 - Paper 1

Step 1

Explain how Figure 2 supports the existence of the antineutrino.

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Answer

The distribution of kinetic energies shown in Figure 2 indicates that the β− particles emitted during the decay of carbon-14 exhibit a range of kinetic energies, with a maximum value that is not fully accounted for. This suggests that some energy is unaccounted for in the decay process. The existence of the antineutrino provides an explanation for this missing energy, as it carries away energy and momentum without being detected.

Step 2

Identify particle X.

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Answer

Particle X is a neutron.

Step 3

Deduce which three gamma photons could have been produced by positron annihilation.

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Answer

The minimum energy produced in the annihilation of the positron and electron is given by the equation:

E=2imes0.51extMeV=1.02extMeV=1.6imes1013extJE = 2 imes 0.51 ext{ MeV} = 1.02 ext{ MeV} = 1.6 imes 10^{-13} ext{ J}

Each gamma photon produced will carry energy equivalent to the total energy divided by the number of photons. Given the energies of the photons from Table 1,

  • G1 is 5.0×1014 J5.0 \times 10^{-14} \text{ J},
  • G2 is 6.6×1014 J6.6 \times 10^{-14} \text{ J},
  • G3 is 1.0×1013 J1.0 \times 10^{-13} \text{ J}.

The total energy for two photons matched the minimum energy produced, confirming that all three photons could be produced in the annihilation.

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