IC2497 is a galaxy that contained a quasar - AQA - A-Level Physics - Question 4 - 2021 - Paper 4

To find the distance, we use the formula for redshift:

d = rac{v}{H_0}

where $v = cz$ and $z$ is the redshift. Given that $z = 0.0516$ and taking $c = 3.0 \times 10^8 \text{ m/s}$, we calculate:

$v = 3.0 \times 10^8 \text{ m/s} \times 0.0516 = 1.55 \times 10^7 \text{ m/s}$

Next, using the Hubble constant $H_0 \approx 70 \text{ km/s/Mpc}$ which is equivalent to $2.3 \times 10^{-18} \text{ s}^{-1}$, we can determine the distance:

$d = \frac{1.55 \times 10^7 \text{ m/s}}{70 \text{ km/s/Mpc}} = \frac{1.55 \times 10^7 \text{ m/s}}{70 \times 10^3 \text{ m/s/Mpc}} = 220.0 \text{ Mpc}$

Thus, the distance from the Earth to IC2497 is approximately 220.0 Mpc.