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Carbon-14 decays into nitrogen-14 with the release of a beta ($\beta^-$) particle and an antineutrino ($ar{ u}_e$) - AQA - A-Level Physics - Question 2 - 2022 - Paper 1

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Carbon-14 decays into nitrogen-14 with the release of a beta ($\beta^-$) particle and an antineutrino ($ar{ u}_e$). Figure 2 shows the distribution of kinetic ener... show full transcript

Worked Solution & Example Answer:Carbon-14 decays into nitrogen-14 with the release of a beta ($\beta^-$) particle and an antineutrino ($ar{ u}_e$) - AQA - A-Level Physics - Question 2 - 2022 - Paper 1

Step 1

State the change of quark character in $\beta^-$ decay

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Answer

In β−\beta^- decay, a down quark changes to an up quark.

Step 2

Explain how Figure 2 supports the existence of the antineutrino

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Answer

Figure 2 shows a distribution of kinetic energies of β−\beta^- particles that indicates they have a range of energies. The presence of an antineutrino is suggested because there should be more energy observed in the decay than what is accounted for by the β−\beta^- particle and the nitrogen-14 produced. The missing energy, evidenced by the observed spectrum, implies that another particle (the antineutrino) carries away this excess energy.

Step 3

Identify particle X

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Particle X is a neutron.

Step 4

Deduce which of the three gamma photons could have been produced by positron annihilation

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Answer

The minimum energy produced in the annihilation of the positron and the electron is calculated to be E=2×0.51 MeV=1.02 MeVE = 2 \times 0.51 \text{ MeV} = 1.02 \text{ MeV}. Therefore, the gamma photons produced during annihilation must each have energies of at least 1.02 MeV1.02 \text{ MeV}. Referring to Table 1, only gamma photons G2 (6.6×10−14extJ6.6 \times 10^{-14} ext{ J}) and G3 (1.0×10−13extJ1.0 \times 10^{-13} ext{ J}) meet this criterion.

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