Complete Table 1 to show the logic outputs for the lamps L1 and L6 - AQA - A-Level Physics - Question 2 - 2017 - Paper 8
Question 2
Complete Table 1 to show the logic outputs for the lamps L1 and L6.
| Number shown on die | Logic inputs | Logic outputs |
|---------------------|--------------|---... show full transcript
Worked Solution & Example Answer:Complete Table 1 to show the logic outputs for the lamps L1 and L6 - AQA - A-Level Physics - Question 2 - 2017 - Paper 8
Step 1
Complete Table 1 to show the logic outputs for the lamps L1 and L6.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Number shown on die
Logic inputs
Logic outputs
B
A
1
0
0
2
0
1
3
1
0
4
1
1
5
1
1
6
0
1
Reset 6 -> 1
0
0
Step 2
Deduce the simplest Boolean expression that can be used to show how output L7 can be controlled by the logic inputs.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The simplest Boolean expression for L7 can be described as:
L7=¬A
This implies L7 is ON when A is OFF.
Step 3
Draw on Figure 6 the logic gate needed and the connections required from the outputs to the reset pin R on the counter so that the counter cycles as required.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To connect the reset pin R properly, attach it to the output conditions from B and C using an AND gate. The output from the AND gate will drive the reset pin to logic 1 when both inputs are 1, ensuring proper reset conditions for the counter.
Step 4
The output of both L3 and L4 can be written as (A . B . C) + (B . C).
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To represent the logic circuit, we can use AND gates for the terms A . B . C and B . C to create the output combining them with an OR gate. This configuration ensures that L3 and L4 light up based on the specified conditions based on the input logic states.