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A diffraction grating has 500 lines per mm - AQA - A-Level Physics - Question 17 - 2018 - Paper 1

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A diffraction grating has 500 lines per mm. When monochromatic light is incident normally on the grating the third-order spectral line is formed at an angle of 60° f... show full transcript

Worked Solution & Example Answer:A diffraction grating has 500 lines per mm - AQA - A-Level Physics - Question 17 - 2018 - Paper 1

Step 1

Calculate the Wavelength of the Monochromatic Light

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Answer

To find the wavelength of the monochromatic light, we can use the diffraction grating equation:

dsin(θ)=mλd \sin(\theta) = m \lambda

Where:

  • dd is the distance between grating lines,
  • θ\theta is the diffraction angle,
  • mm is the order of the spectrum (in this case, m=3m = 3), and
  • λ\lambda is the wavelength.
  1. Calculate dd: Given that there are 500 lines per mm, the distance between grating lines, dd, can be calculated as: d=1500 lines/mm=0.002extmm=2×106extmd = \frac{1}{500 \text{ lines/mm}} = 0.002 ext{ mm} = 2 \times 10^{-6} ext{ m}

  2. Use the Diffraction Equation: Plugging in the known values into the diffraction equation:

    2×106sin(60°)=3λ2 \times 10^{-6} \sin(60°) = 3 \lambda

  3. Calculate sin(60°)\sin(60°): This gives: sin(60°)=32\sin(60°) = \frac{\sqrt{3}}{2}

  4. Rearranging the Equation for λ\lambda: Now we can rearrange the equation to find λ\lambda: λ=2×106323=3×1063m\lambda = \frac{2 \times 10^{-6} \cdot \frac{\sqrt{3}}{2}}{3} = \frac{\sqrt{3} \times 10^{-6}}{3} m

  5. Convert to nm: Calculating this gives us:

    λ0.577×106m=577nm\lambda \approx 0.577 \times 10^{-6} m = 577 nm

By selecting the closest option from the given choices, we find the wavelength of the monochromatic light is approximately 580 nm, thus the correct answer is B.

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