The diagram shows the three lowest energy levels for an atom - AQA - A-Level Physics - Question 15 - 2021 - Paper 1

Since we need the difference between the ground state energy and level 1 energy, we must calculate the energy from the highest frequency available, 2.46 x 10^15 Hz, using the same formula:

$E = (6.63 \times 10^{-34} \ J \cdot s) \times (2.46 \times 10^{15} \ Hz) = 1.63 \times 10^{-18} \ J$

Now, we find the difference between the energy states:

$\Delta E = E_{level1} - E_{ground state} = 1.63 \times 10^{-18} \ J - 3.02 \times 10^{-19} \ J$

This yields:

$\Delta E = 1.33 \times 10^{-18} \ J$

Thus the difference in energy is approximately $1.3 \times 10^{-18} \ J$.