Two cars P and Q leave from the same point and travel in the same direction - AQA - A-Level Physics - Question 13 - 2019 - Paper 1

From the velocity-time graph, at t = 8 s, car Q has a velocity of 40 m/s. Car P has a velocity of 20 m/s at t = 8 s.

The distance traveled by Q can be calculated using the equation:

$ext{Distance} = ext{Velocity} imes ext{Time}$

For Q:

$ext{Distance}_Q = 40 ext{ m/s} imes 8 ext{ s} = 320 ext{ m}$

For P (traveling for 7 seconds):

$ext{Distance}_P = 20 ext{ m/s} imes 7 ext{ s} = 140 ext{ m}$

The distance between Q and P when t = 8 s is given by:

$ext{Distance}_{Q-P} = ext{Distance}_Q - ext{Distance}_P$

$ext{Distance}_{Q-P} = 320 ext{ m} - 140 ext{ m} = 180 ext{ m}$